Answer:
moles of water in of water.
Explanation:
Mass of water =
Molar mass of water = M = 18 g/mol
Moles = n =
So, there are moles of water in of water.
Answer: P = 7.1 atm
Explanation: For this problem we will use Combined Gas Law to solve for the new pressure. But never forget to convert the unit of temperature to Kelvin.
P1V1 /T1 = P2V2/ T2, Derive for P2.
P2 = P1V1T2 / T1V2
= 1.00 atm ( 3.00 L ) ( 323 K) / 273 K ( 0.50 L )
= 7.1 atm
Cancel out the units of L and K and the unit remains is in atm.
<u>Answer: </u> of volume needs to be pipetted out in the test tube.
<u>Explanation:</u>
We are given:
Mass of BSA to be formed = (Conversion factor:
Volume of stock solution = (Conversion factor:
It is also given that for the mass of BSA is 0.5 g, the volume used up is 1 mL
In order to have, 0.005 g, the volume of stock solution needed will be =
Hence, of volume needs to be pipetted out in the test tube.
1 foot = 30.48 cm
3.5 ft * 30.48 cm = 106.68 cm
Answer = 106.68 cm
Hope it helps :)
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Answer: D
Explanation: both experimentation and observation