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nexus9112 [7]
3 years ago
14

¿Cuáles son las grasas e hidróxidos más efectivos en la elaboración de jabón?

Chemistry
1 answer:
d1i1m1o1n [39]3 years ago
6 0

Answer:

Las sales ideales para la saponificacion es la combinacion de grasas complejas con muchas cadenas de trigliceridos y de la soda caustia.

Explanation:

Un ejemplo de estos son la grasa vacuna o la aceite de cocina de consumo tradicional y la soda caustica que es el hidroxido de sodio.

Juntos estos dos productos forman el proceso de saponificacion.

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The Young's modulus values for iron and lead are 210 GPa and 16 GPa, respectively. Based on the information, which statement is
Mrac [35]

Lead is more ductile than iron. The correct option is A. Lead is more ductile than iron

<h3>Young's modulus </h3>

From the question, we are to determine the statement which is true

First, we will define the term <em>Young's modulus </em>

<em>Young's modulus</em> is a measure of the stiffness of an elastic material. It is also given as the ratio of <u>stress </u>to <u>strain</u>. That is,

Young's\ modulus = \frac{Tensile\ stress}{Tensile\ strain}

The greater the modulus, the stiffer the material.

Materials with low Young's modulus tend to be <u>ductile </u>and materials with high Young's modulus tend to be <u>brittle</u>

Since the Young's modulus value for iron is higher than that of lead, then iron is <em>stiffer </em>than lead.

Thus, lead is more ductile than iron. The correct option is A. Lead is more ductile than iron

Learn more on Young's modulus here: brainly.com/question/26660981

3 0
2 years ago
Consider the compound hydroxyapatite, Ca10(PO4)6(OH)2. Name each ion present, give the charge of each ion and show that the form
emmainna [20.7K]
Ca₁₀(PO₄)₆(OH)₂  or  Ca(OH)₂·3Ca₃(PO₄)₂

PO₄³⁻   phosphate ion
OH⁻     oxyhydroxide ion
Ca²⁺     calcium ion

10*(+2)  +  6*(-3)  +  2*(-1) = 0
 10Ca²⁺      6PO₄³⁻      2OH⁻
7 0
3 years ago
Determine if each of the following statements about chiral molecules is True or False and select the best answer from the dropdo
oee [108]

Answer:

See explanation

Explanation:

-)<u> True or False: All R stereocenters are dextrorotatory. </u>

The absolute configuration is based is in specific rules that are not related to the ability to deflect polarized light. <u>FALSE</u>

-)<u> True or False: Chiral centers in organic molecules will have 4 different groups attached to a carbon. </u>

<u />

A chiral carbon by definition is a carbon with 4 groups. <u>TRUE</u>

-)<u> True or False: A racemic mixture has an optical activity of 0. </u>

In a racemic mixture, we have equal amounts of enantiomers, and this cancels out the optical activity. <u>TRUE</u>

-)<u> True or False: Normal linear amines can be chiral centers. </u>

<u />

In primary amines, we have 2 hydrogens. Therefore all the groups can not be different. So, is <u>TRUE</u>

<u />

-)<u>True or False: Compound C has an optical activity of 0. </u>

<u />

We need to know the structure of the compound

<u />

-)<u>True or False: If the R isomer of a molecule has an optical rotation of + 25.7 degree then the S isomer of the molecule will have an optical rotation of -25.7 degree. </u>

<u />

If we have the exact opposite (as we have in this case) the magnitud of the optical activity value will remain and the sign will change. <u>TRUE</u>

-)<u>True or False: A CN is a higher priority than a CH2OH. </u>

<u />

In this case, a carbon is directly bonded to the chiral carbon. The carbon on CN is bonded to a nitrogen atom and the carbon on CH2OH is bonded to an oxygen. So, the CH2OH will have more priority because O has a higher atomic number. <u>FALSE</u>

<u />

-)<u>True or False: All molecules with chiral centers are optically active. </u>

<u />

We can have for example mesocompounds in which the optical activity is canceled out due to symmetry planes. <u>FALSE</u>

<u />

-)<u>True or False: To have an enantiomer a molecule must have at least two chiral centers. </u>

<u />

A pair of enantiomers is made between at least 1 chiral carbon. Enantiomer R and enantiomer S. <u>FALSE</u>

<u />

-)<u>True or False: Chiral molecules are always optically active. </u>

<u />

We can have racemic mixtures or mesocompounds with chiral carbons but without optical activity. <u>FALSE</u>

<u />

-)<u>True or False: A CH2CH2Br is higher priority than a CH2F. </u>

The "Br" atom is bonded in the third carbon (respect to the chiral carbon) and the "F" atom is bonded to the second carbon. Therefore CH2F has more priority than CH2CH2Br. <u>FALSE</u>

-)<u>True or False: Meso molecules with two stereocenters have a R,S configuration. </u>

<u />

On the compounds with R and S configuration at the same time can have symmetry planes so, we will not have optical activity. <u>TRUE</u>

<u />

<u>True or False: Diastereomers have the same physical properties except in a chiral environment. </u>

<u />

All diastereomers have the same physical properties. <u>TRUE</u>

<u />

<u>True or False: Compound H has an optical activity of 0. </u>

<u />

We have to have the structure of the compound.

<u />

<u>True or False: A C=C double bond is higher priority than a -CH(CH3)2.</u>

<u />

In the case of C=C, we can say that is equivalent to two carbon bonds without hydrogens. Therefore C=C has higher priority. <u>TRUE</u>

<u />

6 0
4 years ago
The time necessary for the decay of one- half sample of a radioactive substance is a _____. mass defect daughter half life nucli
Mazyrski [523]

Answer: half life

Explanation: Radioactive decay follows first order kinetics and the time required for the decay of a radioactive material is calculated as follows:

t=\frac{2.303}{k}\hspace{1mm}log\frac{x}{a}

t= time required

k= disintegration constant

x= amount of substance left after time t

a= initial amount of substance

when one half of the sample is decayed, one half of the sample remains and t can be represented as t_{1/2}

at t= t_{1/2}, x=\frac{a}{2}

t_{1/2}=\frac{2.303}{k}\hspace{1mm}log\frac{a/2}{a}

t_{1/2}=\frac{0.693}{k}

3 0
3 years ago
Read 2 more answers
6Most types of heather grow better in acidic soil.
lana66690 [7]

Answer:

Its a and e

Explanation:

So ez give me brainliest nd a thanks plz

3 0
2 years ago
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