- Initial velocity=u=0m/s
- Final velocity=v=120m/s
- Distance between course=s=400m
- Acceleration be a
According to thrid equation of kinematicsthird equation of kinematics
Isolate the equation for a
Answer:
Question: What is the current in a 160V circuit if the resistance is 2Ω?
Answer:
Voltage ( V ) = 160V
Resistance ( R ) = 2Ω
Current ( I ) = ?
By Ohms law
⇒ V = IR
⇒ 160 = I × 2
⇒ I = 160 / 2 = 80A
\rule{200}2
Question: What is the current in a 160V circuit if the resistance is 20Ω?
Answer:
Voltage ( V ) = 160V
Resistance ( R ) = 20Ω
Current ( I ) = ?
By Ohms law
⇒ V = IR
⇒ 160 = I × 20
⇒ I = 160 / 20 = 8A
\rule{200}2
Question: What is the current in a 160V circuit if the resistance is 10Ω?
Answer:
Voltage ( V ) = 160V
Resistance ( R ) = 10Ω
Current ( I ) = ?
By Ohms law
⇒ V = IR
⇒ 160 = I × 10
⇒ I = 160 / 10 = 16A
\rule{200}2
Question: Based on questions 2, 3, and 4, what happens to the current in a circuit as the resistance decreases? Increases?
Answer:
From ohms law
⇒ I = V / R
If we take Voltage as proportionality constant
⇒ I ∝ 1 / R
So, we can conclude that current is inversely proportional to resistance.
From 2, 3, 4 questions we can conclude that,
If resistance increases, current decreases and when resistance decreases, current increases.
\rule{200}2
Question: What voltage is required to move 6A through 5Ω?
Answer:
Resistance ( R ) = 5Ω
Current ( I ) = 6A
Voltage ( V ) = ?
By Ohms law
⇒ V = IR
⇒ V = 6 × 5
⇒ V = 30V
\rule{200}2
Question: What voltage is required to move 6A through 10Ω?
Answer:
Resistance ( R ) = 10Ω
Current ( I ) = 6A
Voltage ( V ) = ?
By Ohms law
⇒ V = IR
⇒ V = 6 × 10
⇒ V = 60V
\rule{200}2
Question:What voltage is required to move 6A through 20Ω?
Answer:
Resistance ( R ) = 20Ω
Current ( I ) = 6A
Voltage ( V ) = ?
By Ohms law
⇒ V = IR
⇒ V = 6 × 20
⇒ V = 120V
\rule{200}2
Answer:
- Our final answer is 15 kg .
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Answer:
The bird's speed immediately after swallowing is 4.98 m/s.
Explanation:
Given that,
Mass of bird = 290 g
Speed = 6.2 m/s
Mass of sees = 9.0 g
Speed = 34 m/s
We need to calculate the bird's speed immediately after swallowing
Using conservation of momentum
Put the value into the formula
Hence, The bird's speed immediately after swallowing is 4.98 m/s.