Answer:
B
Explanation:
if it is ganing more energy than it is giving off (which of cource it isint or we whould be baken) then it whould heat up
4. The answer is that you will see the same sights as when you are resting. That is because you and mirror are in rest one relative another. If your relative speed is 0, it doesn't matter how quickly you both travel in relation to other objects.
5. The relativistic effects will not alter if the speed of light is reduced to 50m/s. According to the principle of constancy (2nd postulate), the upper limit of speed is 50m/s, which will be impossible for material objects to achieve because as the speed of light decreases, the sizes of humans and all other materials decrease as well, decreasing our relativistic velocity and thus making c=50m/s unattainable for material objects, and thus the relativistic effects will remain unchanged. A pedestrian must use caution when crossing the roadway. Let's assume you see a car arriving at 60 kilometers per hour, or 16.666 meters per second, from a distance of 100 meters. It'll take 6 seconds to arrive, giving you plenty of time to cross the street. Because the light reflected from the car to your eyes left the car two seconds ago, the car will reach at your location in four seconds and hit you (if the car is travelling in the lane on the far side of the road). It looks to you that approaching automobiles traveling at the legal limit are traveling at a speed of 100 / 4 = 25 m/s, which is 50% faster than the genuine speed of 16.666 m/s. When considering whether or not it is safe to cross the road, one would quickly become accustomed to this.
6.
Answer:
Green, tall, weird language, maybe has only one eye or more, has an egg-shaped spaceship.
Answer:
A) 7500[N]
Explanation:
This is a problem where we have to apply the pascal principle, in this case replace the given values in the given equation:
F1 = 2500 [N]
A1 = 0.06 [m^2]
A2 = 0.18 [m^2]
![F_{2}=A_{2}*\frac{F_{1}}{A_{1}} \\F_{2}=0.18*\frac{2500}{0.06}\\ F_{2}= 7500[N]](https://tex.z-dn.net/?f=F_%7B2%7D%3DA_%7B2%7D%2A%5Cfrac%7BF_%7B1%7D%7D%7BA_%7B1%7D%7D%20%5C%5CF_%7B2%7D%3D0.18%2A%5Cfrac%7B2500%7D%7B0.06%7D%5C%5C%20F_%7B2%7D%3D%207500%5BN%5D)
Helium exhibits more visible emission lines or spectral lines than hydrogen is due to the fact that helium has two electrons compared to hydrogen which only has one electron. The greater the chance of the energy levels falling within the visible range when there's more energy level. Spectral lines are usually the result of the interaction of quantum system, usually atoms but can also be the molecules or the atomic nuclei sometimes together with a single photon. Whenever photon has the right amount of energy in order to allow changes in energy state, the system, or the electron changing orbitals will absorbed the photon, then will be emitted whether in same frequency with the original of in cascade.
