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Eddi Din [679]
3 years ago
13

Two point charges are brought closer together, increasing the force between them by a factor of 17. By what factor was their sep

aration decreased? In other words, if r1 is the original separation and r2 is the final separation, what is the ratio r1/r2?
Physics
1 answer:
nignag [31]3 years ago
6 0

Answer:

\dfrac{r_1}{r_2}=4.123

Explanation:

Given:

Final force between them=17(initial force between them)

initial separation between them r_1

Final separation between them r_2

Let Q and q be the charges on them then

F_2=17F_1\\\dfrac{kQq}{r_2^2}=17\dfrac{kQq}{r_1^2}\\\dfrac{r_1^2}{r_2^2}=17\\\dfrac{r_1}{r_2}=4.123

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