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Stolb23 [73]
4 years ago
7

If you push a 1000 kg box so in 2 seconds its velocity changes from 5m/s to 10 m/s how much force do you have to apply?

Physics
1 answer:
USPshnik [31]4 years ago
6 0

Answer:

  Force required to change velocity = 2.5 kN

Explanation:

 Force required = Mass of box x Acceleration of box

 Acceleration of box = Change in velocity of box / Time.

 Mass of box, m=   1000 kg

 Acceleration of box, a = (10 - 5)/2 = 5/2

                                       = 2.5 m/s²

  Force required = ma

                             = 1000 x 2.5 = 2500 N = 2.5 kN

  Force required to change velocity = 2.5 kN

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The mass is moving by uniformly accelerated motion, with initial velocity v_i=7.50 m/s and acceleration a=0.55 m/s^2. Its position at time t is given by the following law:
x(t)=v_i t + \frac{1}{2}at^2
where we take the initial position x_i=0 since we are only interested in the distance traveled by the mass.

If we put x(t)=d=3.5 km=3500 m into the equation, the corresponding time t is the time it takes for the mass to travel this distance:
\frac{1}{2}at^2+v_it-d=0
4.9t^2+7.5t-3500 =0
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3 years ago
11. Find the direction of the Force
d1i1m1o1n [39]

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The conductors that carry the current to electrical devices and ? equipment are the heart of all electrical systems. There are a
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utilization / effects

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3 years ago
The power output of a tuba is 0.35 W. At what distance is the sound
STALIN [3.7K]

The distance of the sound from the tuba is 4.82 m.

<h3>Area of the tube</h3>

The area of the tuba is calculated as follows;

I = P/A

where;

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A = P/I

A = 0.35 / (1.2 x 10⁻³)

A = 291.67 m²

<h3>Distance of the sound</h3>

Area = 4πr²

r = \sqrt{\frac{A}{4\pi} } \\\\r = \sqrt{\frac{291.67}{4\pi} } \\\\r = 4.82 \ m

Thus, the distance of the sound from the tuba is 4.82 m.

Learn more about intensity of sound here: brainly.com/question/4431819

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