If you push a 1000 kg box so in 2 seconds its velocity changes from 5m/s to 10 m/s how much force do you have to apply?
1 answer:
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Answer:
C. The amount of force applied to rock one was half the amount of force applied to rock two during the eruption.
Explanation:
A force is an agent which changes the state of an object well applied to it. Second Newton's law of motion state's that;
F = ma
where F is the force, m is the mass of the object and a is the acceleration of the object.
In the given question,
Mass of first rock = 10 kilograms
Mass of the second rock = 20 kilograms
Acceleration of the two rocks = 600 m/
Thus,
Force on the first rock = ma
= 10 x 600
= 6000 N
Force on the second rock = 20 x 600
= 12000 N
Therefore, it can be observed that the amount of force applied to rock one was half the amount of force applied to rock two during the eruption.
Explanation:
Given that,
Length of the spring, l = 50 cm = 0.5 m
Mass connected to the end, m = 330 g = 0.33 kg
The mass is released and falls, stretching the spring by 30 cm before coming to rest at its lowest point. On applying Newton's second law, 10 cm below the release point, x = 15 cm
(a) When the mass is connected, the force of gravity is balanced by the force in spring.
(b) The amplitude of the oscillation will be 15 cm as it is half of the total distance travelled.
(c) The frequency of the oscillation is given by :
Hence, this is the required solution.