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adoni [48]
3 years ago
11

The force on a current-carrying wire is a maximum when the current is moving parallel to a magnetic field. true or false

Physics
1 answer:
Anon25 [30]3 years ago
8 0
The force is given by F=iL×B  where i is current, L is the path the current follows (the wire path) and B is the magnetic field.  Also recall that the × symbol is the vector cross product, which can be expressed by the sine of the angle between the vectors L and B.  Therefore we can also say F=iLBsin(θ).  Do you know what value of θ makes sin(θ) the largest?  This will tell you if parallel or perpendicular makes the force strongest.  For one value of θ it will be zero, and for the other it will be maximized.
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alekssr [168]

Answer:

1.5106 cm

Explanation:

The beat frequency is equal to the absolute value of the difference between the frequencies of the two signals:

f_B = |f_1 - f_2|

using the wave equation, we can re-write each frequency as

f=\frac{c}{\lambda}

where c is the speed of light and \lambda is the wavelength. Therefore,

f_B = |\frac{c}{\lambda_1}-\frac{c}{\lambda_2}|

where:

f_B = 140 MHz = 140\cdot 10^6 Hz is the beat frequency

\lambda_1 = 1.50 cm = 0.015 m is the wavelength of the first generator

\lambda_2 is the wavelength of the second generator

We also know that the second generator emits the longer wavelength, so we already know that the term inside the module is positive. Therefore, we can now solve for \lambda_2:

f_B = c(\frac{1}{\lambda_1}-\frac{1}{\lambda_2})\\\lambda_2=(\frac{1}{\lambda_1}-\frac{f_B}{c})^{-1}=(\frac{1}{0.015}-\frac{140\cdot 10^6}{3\cdot 10^8})^{-1}=0.015106 m = 1.5106 cm

4 0
3 years ago
Which of the following is NOT a step in the technical design<br> process?
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Mechanical life support system

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The life support system may not only provide water, air and food but it should also keep a proper check on the maintenance of body pressure, temperature, management of the waste product and the absorption or the radiations from the body itself.

Thus mechanical life support system are designed with the hep of high engineering techniques for the safety and security as these are life-critical.

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3 years ago
A solar cell, 3.0 cm square, has an output of 350 mA at 0.80 V when exposed to full sunlight. A solar panel that delivers close
Vesna [10]

Answer:

You will need 450 cells (3 cm each) to meet the voltage/current requirement.

The panel must be 3 cells in one side, by 150 cell in another side. 1350 cm^2 or 0.135 m^2. They must be connected 3 in row in parallel (to add current), then each of the former group must be connected in series to meet the voltage, so it would be 150 rows of connected in series.

The panel can be optimized using a voltage inverter, to convert current to voltage. In this way, less cells can be used achieving the same output specs.

Explanation:

To meet the voltage:

120 [v] required voltage

0.8 [v] voltage of each cell

\frac{120}{0.8} =150[v]\\

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1/0.35=3 cell So we need 3 cells in parallel to add the currents and meet the requirement.

See the attached figure

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