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3 years ago

The force on a current-carrying wire is a maximum when the current is moving parallel to a magnetic field. true or false

1 answer:

8 0

The force is given by F=iL×B where i is current, L is the path the current follows (the wire path) and B is the magnetic field. Also recall that the × symbol is the vector cross product, which can be expressed by the sine of the angle between the vectors L and B. Therefore we can also say F=iLBsin(θ). Do you know what value of θ makes sin(θ) the largest? This will tell you if parallel or perpendicular makes the force strongest. For one value of θ it will be zero, and for the other it will be maximized.

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shows a conical pendulum, in which the bob (the small object at the lower end of the cord) moves in a horizontal circle at const

Contact [7]

Answer:

a) $T=0.40 N$

b) $T=1.9 s$

Explanation:

Let's find the radius of the circumference first. We know that bob follows a circular path of circumference 0.94 m, it means that the perimeter is 0.94 m.

The perimeter of a circunference is:

$P=2\pi r=0.94$

$r=\frac{0.94}{2\pi}=0.15 m$

Now, we need to find the angle of the pendulum from vertical.

$tan(\alpha)=\frac{r}{L}=\frac{0.15}{0.90}=0.17$

$\alpha=9.44 ^{\circ}$

Let's apply Newton's second law to find the tension.

$\sum F=ma_{c}=m\omega^{2}r$

We use centripetal acceleration here, because we have a circular motion.

The vertical equation of motion will be:

$Tcos(\alpha)=mg$ (1)

The horizontal equation of motion will be:

$Tsin(\alpha)=m\omega^{2}r$ (2)

a) We can find T usinf the equation (1):

$T=\frac {mg}{cos(\alpha)}=\frac{0.04*9.81}{cos(9.44)}=0.40 N$

We can find the angular velocity (ω) from the equation (2):

$\omega=\sqrt{\frac{Tsin(\alpha)}{mr}}=3.31 rad/s$

b) We know that the period is T=2π/ω, therefore:

$T=\frac{2\pi}{\omega}=\frac{2\pi}{3.31}=1.9 s$

I hope it helps you!

8 0

2 years ago

The shortest wavelengths that we can see are experienced as ______ colors.

nadezda [96]

Violet. Red is longest wavelength and lowest frequencyViolet is shortest wavelength and highest frequencyThe visible part of the whole electromagnetic spectrum.Sort of thing you see if you look through a prism in an laboratory optical spectrometer.

8 0

3 years ago

An object accelerates 3 m/s2 , when a force of 6 N acts on it. What is the object’s mass

telo118 [61]

Answer:

Explanation:

The mass of the object can be found by using the formula

$m = \frac{f}{a} \\$