Answer:
Object D
Explanation:
Use Newton's Second Law to determine the acceleration that each object has.
The force applied in both cases is 50 N, but the mass for object C and object D is different.
Let's start with object C first:
- F = ma
- 50 N = 10 kg · a
- 50 = 10a
- 5 = a
The acceleration object C undergoes is 5 m/s².
Now let's calculate object D next:
- F = ma
- 50 N = 2 kg * a
- 50 = 2a
- 25 = a
The acceleration object D undergoes is 25 m/s².
Object D has greater acceleration because it has a smaller mass. The object with a smaller mass will accelerate more in order to satisfy Newton's 2nd Law.
Answer:
The answer is C!!!!!!!
Becuz meters and seconds are derived into m/s²
Explanation:
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Answer:
No, it is not proper to use an infinitely long cylinder model when finding the temperatures near the bottom or top surfaces of a cylinder.
Explanation:
A cylinder is said to be infinitely long when is of a sufficient length. Also, when the diameter of the cylinder is relatively small compared to the length, it is called infinitely long cylinder.
Cylindrical rods can also be treated as infinitely long when dealing with heat transfers at locations far from the top or bottom surfaces. However, it not proper to treat the cylinder as being infinitely long when:
* When the diameter and length are comparable (i.e have the same measurement)
When finding the temperatures near the bottom or top of a cylinder, it is NOT PROPER TO USE AN INFINITELY LONG CYLINDER because heat transfer at those locations can be two-dimensional.
Therefore, the answer to the question is NO, since it is not proper to use an infinitely long cylinder when finding temperatures near the bottom or top of a cylinder.
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