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3 years ago

I need an answer to this

Mathematics

1 answer:

Ulleksa [173]3 years ago

4 0

Answer:

x=3

Step-by-step explanation:

x+1*5=20

x*5=15

15/5=3

Hope this helps! :)

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Quadrilateral CAMP below is a rhombus. the length PQ is (x+2) units, and the length of QA is (3x-14) units. Which statements bes

valentinak56 [21]

Answer:

<h3>Q cuts the diagonal PA into 2 equal halves, since the diagonals of rhombus meet at right angles.</h3><h3>The value of x is 8.</h3>

Step-by-step explanation:

Given that Quadrilateral CAMP below is a rhombus. the length PQ is (x+2) units, and the length of QA is (3x-14) units

From the given Q is the middle point, which cut the diagonal PA into 2 equal halves.

By the definition of rhombus, diagonals meet at right angles.

Implies that PQ = QA

x+2 = 3x - 14

x-3x=-14-2

-2x=-16

2x = 16

dividing by 2 on both sides, we will get,

$x =\frac{16}{2}$

<h3>∴ x=8</h3><h3>Since Q cuts the diagonal PA into 2 equal halves, since the diagonals of rhombus meet at right angles we can equate x+2 = 3x-14 to find the value of x.</h3>

The line segment $\overrightarrow{PA}=\overrightarrow{PQ}+\overrightarrow{QA}$

$\overrightarrow{PA}=x+2+3x-14$

$=4x-12$

$=4(8)-12$ ( since x=8)

$=32-12$

$=20$

<h3>∴ $\overrightarrow{PA}=20$ units</h3>

3 0

3 years ago

the coordinates of the endpoints of AB are A (-8, -2) and B(16,6). Point P is on AB what are the coordinates of point P such tha

garri49 [273]

We have that
<span>A (-8, -2) and B(16,6)

step 1
find the distance AB in the x coordinates
dABx=(16-(-8))-----> 24 units

step 2
find coordinate x of P (Px)
Px=Ax+(3/5)*dABx------> Px=(-8)+(3/5)*24----> 6.4

step 3
F</span>ind the distance AB in the y coordinates
dABy=(6-(-2))-----> 8 units

step 4
find coordinate y of P (Py)
Py=Ay+(3/5)*dABy------> Py=(-2)+(3/5)*8----> 2.8

the coordinates of P are (6.4,2.8)

see the attached figure

6 0

3 years ago

In the diagram below, m_MON = 1249, m _ MOP = 2x + 1, and m2 NOP = 2x

miv72 [106K]

Answer:

The answer is below

Step-by-step explanation:

The Angle Addition Postulate states that the measure of an angle formed by two or more angles which are placed side by side is the sum of the measures of the two angles.

Therefore:

∠MON = ∠MOP + ∠NOP (angle addition postulate)

Substituting values gives:

124 = (2x + 1) + (2x + 1)

124 = 2x + 2x + 1 + 1

124 = 4x + 2

subtracting 2 from both sides of the equation:

124 - 2 = 4x + 2 - 2

4x = 122

Dividing through by 4:

4x / 4 = 122 / 4

x = 30.5