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elixir [45]
3 years ago
15

Calculate the number-average molecular weight of a random nitrile rubber [poly(acrylonitrile-butadiene) copolymer] in which the

fraction of butadiene repeat units is 0.27; assume that this concentration corresponds to a degree of polymerization of 2000.
Chemistry
1 answer:
SCORPION-xisa [38]3 years ago
7 0

Answer:

106,504 g/mol

Explanation:

The two repeat units at the polymer are the acrylonitrile and the butadiene. If the fraction of repeat of butadiene is 0.27, the fraction of repeat of units of acrylonitrile must be 0.73.

The acrylonitrile repeat unit has 3 carbons atoms, 1 nitrogen atom, and 3 hydrogen atoms. So, the molecular weigth for it is:

mac = 3*mC + 1*mN + 3*mH

mC = 12 g/mol; mN = 14 g/mol; mH = 1g/mol

mac = 3*12 + 14 + 3*1 = 53 g/mol

The butadiene repeat unit has 4 carbons atoms and 6 hydrogen atoms. Thus, the molecular weight is:

mbu = 4*12 + 6*1 = 54 g/mol

The average repeat unit molecular weight is the fractions multiplied by the molecular weight of the repeat unities:

m = 0.73*53 + 0.27*54 = 53.27 g/mol

The number-average molecular weight is the average repeat unit molecular weight  multiplied by the degree of polymerization:

M = 53.27*2000

M = 106,504 g/mol

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A reaction mixture at equilibrium at 175 k contains ph2 = 0.958 atm, pi2 = 0.877 atm, and phi = 0.020 atm. a second reaction mix
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 from ICE table
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Kp1 = P(HI)^2 / p(H2)*p(I2) for mix 1
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we can see that Kp1< Kp2 that means that the sec mixture is not at equilibrium. It will go left to reduce its products and increase reactant to reduce the Kp value to achieve equilibrium.

and the partial pressure of Hi when mix 2 reach equilibrium is:
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8 0
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QUESTION 5
amid [387]

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m+/+

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para +/-

compe-/-

Explanation:

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