Of what?i cant see any pic here?
Answer:
<h2>A. The image shows Boyle's Law because volume decreases as pressure increases.</h2>
Explanation:
According to Boyle's Law, at constant temperature, pressure and volume have inverse relation that is as pressure would increase, volume would decrease.
According to Charles Law, at constant pressure, the volume is directly proportional to temperature.
According to the given graph and diagram, the temperature is constant and volume and pressure have inverse relation.
Thus, option A is correct.
Answer: 1) only a salt and water
An acid and base reacts together to undergo neutralization to form salt and water.

where HCl is an acid and NaOH is a base to form salt (NaCl) and water
.
Answer: 2) The formula of the hydrogen ion is often written as
.
All acids dissociate in water to give
ions.
Answer: 3) Arrhenius acids are substances that ionizes to yield protons in aqueous solution.

Arrhenius bases are substance that ionizes to yield hydroxide ions in aqueous solution.

Answer: 4) A conjugate acid base pair transfers hydrogen ion.
Here
accepts a proton and thus act as a base and the corresponding
is its conjugate acid.
Answer: 5) Bronsted Lowry acid is a substance that donates protons. Bronsted Lowry base is a substance that accepts protons.
and 

is a acid which accepts proton and thus acts as base to form conjugate acid
.
Answer:
The diameter of the oil molecule is
.
Explanation:
Mass of the oil drop = 
Density of the oil drop = 
Volume of the oil drop: v


Thickness of the oil drop is 1 molecule thick.So, let the thickness of the drop or diameter of the molecule be x.
Radius of the oil drop on the water surface,r = 41.8 cm = 0.418 m
1 cm = 0.01 m
Surface of the sphere is given as: a = 

Volume of the oil drop = v = Area × thickness


The thickness of the oil drop is
and so is the diameter of the molecule.
1°/ . 2 Al + 6 HCl → 2 AlCl3 + 3 H2
<span>k1 = n(Al) / 2 = 4,5 / 2 = 2,25 </span>
<span>k2 = n(HCl) / 6 = 11,5 / 6= 1,92 </span>
<span>k2 < k1 ==> HCl is the limiting reactant </span>
<span>6 mol of HCl ---> 2 mol of H2 </span>
<span>11,5 mol of HCl ---> 3,83 mol of H2 </span>