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3 years ago

The table shows the data of a random sample of fish that were collected from and later released into a lake.

1 answer:

6 0

280 eels

92 + 56 + 52 = 200
eel = 56/200

56 *5     x
----- =   --------
200   *5 1000
56(5) = 280 x = 280

56/200 = 7/25
7/25 = 280/1000

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Need help with this !!!!

Aleksandr [31]

y = - 4x + - 8 is equation of slope-intercept form.

What is in slope-intercept form?

Given the slope of the line and the intercept it forms with the y-axis, one of the mathematical forms used to derive the equation of a straight line is called the slope intercept form.
Y = mx + b, where m is the slope of the straight line and b is the y-intercept, is the slope intercept form.

the equation of slope - intercept form

y = mx + c

( -1 , -4 ) is point shown in graph

slope = -y/x

= - ( -4)/-1 = 4/-1 = -4

- 4 = -4 * - 1 + c

- 4 = 4 + c

c = - 4 - 4 = - 8

put value of c in the equation of slope - intercept form

y = - 4x + - 8

Learn more about slope-intercept form

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8 0

1 year ago

Find the missing angles in the diagram below:

Bezzdna [24]

Answer:

B = 50°

D = 40°

A = 90°

C = A = 90°

Step-by-step explanation:

I hope that it's a correct answers.

3 0

3 years ago

Which is not a property of a parallelogram?

Nookie1986 [14]

"Contains four right angles" is the one among the following choices given in the question that is <span>not a property of a parallelogram. Parallelograms can have angles that are not ninety degrees. The correct option among all the options that are given in the question is the second option or option "B". </span>

3 0

3 years ago

A 1000-liter (L) tank contains 500 L of water with a salt concentration of 10 g/L. Water with a salt concentration of 50 g/L flo

djverab [1.8K]

Answer:

a) $y(t)=50000-49990e^{\frac{-2t}{25}}$

b) $31690.7 g/L$

Step-by-step explanation:

By definition, we have that the change rate of salt in the tank is $\frac{dy}{dt}=R_{i}-R_{o}$ , where $R_{i}$ is the rate of salt entering and $R_{o}$ is the rate of salt going outside.

Then we have, $R_{i}=80\frac{L}{min}*50\frac{g}{L}=4000\frac{g}{min}$ , and

$R_{o}=40\frac{L}{min}*\frac{y}{500} \frac{g}{L}=\frac{2y}{25}\frac{g}{min}$

So we obtain. $\frac{dy}{dt}=4000-\frac{2y}{25}$ , then

$\frac{dy}{dt}+\frac{2y}{25}=4000$ , and using the integrating factor $e^{\int {\frac{2}{25}} \, dt=e^{\frac{2t}{25}$ , therefore $(\frac{dy }{dt}+\frac{2y}{25}}=4000)e^{\frac{2t}{25}$ , we get $\frac{d}{dt}(y*e^{\frac{2t}{25}})= 4000 e^{\frac{2t}{25}$ , after integrating both sides $y*e^{\frac{2t}{25}}= 50000 e^{\frac{2t}{25}}+C$ , therefore $y(t)= 50000 +Ce^{\frac{-2t}{25}}$ , to find $C$ we know that the tank initially contains a salt concentration of 10 g/L, that means the initial conditions $y(0)=10$ , so $10= 50000+Ce^{\frac{-0*2}{25}}$

$10=50000+C\\C=10-50000=-49990$

Finally we can write an expression for the amount of salt in the tank at any time t, it is $y(t)=50000-49990e^{\frac{-2t}{25}}$

b) The tank will overflow due Rin>Rout, at a rate of $80 L/min-40L/min=40L/min$ , due we have 500 L to overflow $\frac{500L}{40L/min} =\frac{25}{2} min=t$ , so we can evualuate the expression of a) $y(25/2)=50000-49990e^{\frac{-2}{25}\frac{25}{2}}=50000-49990e^{-1}=31690.7$ , is the salt concentration when the tank overflows

4 0

3 years ago

En un pastel que se quiere repartir a 5 personas, se logran generar 8 piezas al cortarlo, cual de las siguientes expresiones ref

Anon25 [30]

Answer:

La respuesta es 1/5.

Step-by-step explanation:

porque el 1 pastel se divide en 5 personas.

Espero que esto ayude.

8 0

3 years ago