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4 years ago

Show that the expression vf = vi + at is dimensionally correct

1 answer:

4 0

To show that the expression given is dimensionally correct, we can do a dimensional analysis where we write the units of each term in the expression.

vf [=] vi + at
m/s [=] m/s+ (m/s²) (s)
m/s [=] m/s+ m/s
m/s [=] m/s

Therefore, the expression is dimensionally correct.

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Unpolarized light with intensity S is incident on a series of polarizing sheets. The first sheet has its transmission axis orien

jeka94

Answer:

Explanation:

Given

Initial Intensity of light is S

when an un-polarized light is Passed through a Polarizer then its intensity reduced to half.

When it is passed through a second Polarizer with its transmission axis $\theat =45^{\circ}$

$S_1=S_0\cos ^2\theta$

here $S_0=\frac{S}{2}$

$S_1=\frac{S}{2}\times \frac{1}{(\sqrt{2})^2}$

$S_1=\frac{S}{4}$

When it is passed through third Polarizer with its axis $90^{\circ}$ to first but $\theta =45^{\circ}$ to second thus $S_2$

$S_2=S_0\cos ^2\theta$

$S_2=\frac{S}{4}\times \frac{1}{2}$

$S_2=\frac{S}{8}$

When middle sheet is absent then Final Intensity will be zero

3 0

3 years ago

I. )Which unit can be used to express force?

frutty [35]

The correct choices, sequentially and respectively, are c., d., d., a., d.

7 0

3 years ago

At which position would a person on Earth be able to view a solar eclipse? A B C D

sweet-ann [11.9K]

The answer would be A, since at that position the Earth is fully/partially being engulfed in a shadow cast by the moon from the sun’s rays.

Hope this helps!

5 0

3 years ago

If a small motor does 520 J of work to move a toy car 260 m in 3.0 seconds, how much power is being applied by the motor?

Lubov Fominskaja [6]

Answer:

P = 173.33 [W]

Explanation:

Power is defined as the amount of work done over a given time.

W = work = 520 [J]

t = time = 3 [s]

P = power [w]

Therefore by working relationship over time we can calculate the power.

$P =W/t\\P = 520/3\\P=173.33[W]$

4 0

3 years ago

A 26 kg child is coasting at 2.0 m/s over flat ground in a 5.0 kg wagon. The child drops a 1.5 kg ball from the side of the wago

RoseWind [281]

Answer:

Final speed = 2.067 m/s

Explanation:

We are told that the child weighs 26 kg.

Also, that the wagon weighs 5kg.

Thus,initial mass of the child and wagon with ball is;

m_i = 26 + 5 = 31 kg.

Also, we are told that the child now dropped 1.5 kg ball from the wagon. So,

Final mass is;

m_f = 26 + 5 - 1 = 30 kg

Now, from conservation of linear momentum, we know that;

Initial momentum = final momentum

Thus;

m_i * v_i = m_f * v_f

Where v_i is initial velocity and v_f is final velocity.

Making v_f the subject, we have;

v_f = (m_i * v_i)/m_f

We are given that initial velocity v_i = 2 m/s

Plugging in the relevant values, we have;

v_f = (31 * 2)/30

v_f = 2.067 m/s

7 0

3 years ago