Question

A charge Q is uniformly spread over one surface of a very large nonconducting square elastic sheet having sides of length d. At a point P that is 1.25 cm outside the sheet, the magnitude of the electric field due to the sheet is E. If the sheet is now stretched so that its sides have length 2d, what is the magnitude of the electric field at P?
A) 4E B) 2E C) E D) E/2 E) E/4

Answer 1

Answer:

Explanation:

Given

Charge Q is uniformly spread over large non-conducting Elastic sheet      

Electric field due to non-conducting Elastic sheet

$E=\frac{\sigma }{2\epsilon }$

where $\sigma =$surface charge density$=\frac{q}{d^2}$

$E=\frac{\frac{q}{d^2}}{2\epsilon }$

for side 2d Electric Field is given by

$E'=\frac{\frac{q}{2d^2}}{2\epsilon }$

$E'=\frac{1}{4}\times \frac{\frac{q}{d^2}}{2\epsilon }$

$E'=\frac{E}{4}$