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Sergio [31]
4 years ago
11

Calculate the pressure on the bottom of a swimming pool 3. 5 m deep. How does the pressure compare with atmospheric pressure, 10

5 Pa? (density of water=1000kg/m3 ).
Physics
1 answer:
Nostrana [21]4 years ago
5 0

Answer:

  1.343 atm

Explanation:

The mass of water above 1 square meter of swimming pool bottom is ...

  M = (3.5 m)·(1000 kg/m^3) = 3500 kg/m^2

Then the force exerted by the water on the pool bottom is ...

  F = Mg = (3500 kg/m^2)(9.8 m/s^2) = 34300 N/m^2 = 34300 Pa

Compared with atmospheric pressure, this is ...

  34,300/10^5 = 0.343 . . . . atmospheres

Added to the atmospheric pressure on the water's surface, the total pressure on the pool bottom is 1.343 atmospheres.

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A furlong is 220 yd. A fortnight is 2 weeks. Convert a speed of one furlong per fortnight to millimeters per second.
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Answer:

0.1663\frac{mm}{s}

Explanation:

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3 years ago
Plz plz help ...i really need steps for this answer
bija089 [108]

Answer:

3.9 seconds

Explanation:

Use constant acceleration equation:

y = y₀ + v₀ t + ½ at²

where y is the final position,

y₀ is the initial position,

v₀ is the initial velocity,

a is the acceleration,

and t is time.

Given:

y = 0 m

y₀ = 15 m

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a = -9.8 m/s²

Substituting values:

0 = 15 + 15t + ½ (-9.8) t²

0 = 15 + 15t − 4.9t²

0 = 4.9t² − 15t − 15

Solve with quadratic formula:

t = [ -b ± √(b² − 4ac) ] / 2a

t = [ 15 ± √((-15)² − 4(4.9)(-15)) ] / 2(4.9)

t = [ 15 ± √(225 + 294) ] / 9.8

t = (15 ± √519) / 9.8

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It takes 3.9 seconds for the stone to reach the bottom of the well.

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