Answer:
1.343 atm
Explanation:
The mass of water above 1 square meter of swimming pool bottom is ...
M = (3.5 m)·(1000 kg/m^3) = 3500 kg/m^2
Then the force exerted by the water on the pool bottom is ...
F = Mg = (3500 kg/m^2)(9.8 m/s^2) = 34300 N/m^2 = 34300 Pa
Compared with atmospheric pressure, this is ...
34,300/10^5 = 0.343 . . . . atmospheres
Added to the atmospheric pressure on the water's surface, the total pressure on the pool bottom is 1.343 atmospheres.
