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sdas [7]
4 years ago
15

What is the following quotient? Square root 120/ square root 30 2 4 210 3/10

Mathematics
1 answer:
svlad2 [7]4 years ago
5 0

Answer:

2

Step-by-step explanation:

sqrt(120)/ sqrt(30)

We know that sqrt(a)/ sqrt(b) = sqrt(a/b)

sqrt(120/30)

sqrt(4)

2

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If point Cis between points A and B, then AC + __ = AB.<br> A. ABC<br> B. CA<br> C. BC<br> D. AB
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I think it’s C. I also just posted a question so if anyone could answer or look at the comments that would be AMAZING
6 0
3 years ago
Sam and Bethan share £54 in the ratio 5:4. how much will each person get
Sunny_sXe [5.5K]
Given :- 
sam and Bethan shareare in the ratio 5:4 respectively. 
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 Let Sams share is be x ie = 5 
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 Therefore the persons share is (particular persons share / total no of share) *
total value of money 
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5 0
3 years ago
0.782 ___ 0.784<br> I Need HElP NOW!
Alexandra [31]
0.782 < 0.784
this is correct because 2 is less than 4
7 0
3 years ago
Read 2 more answers
Plz help ill give u brainlist
serg [7]
Area of the base = 6 (1/2 x 4.3 x 5) = 64.5cm

Area of the top = area of the base = 64.5cm

Area of the 6 side rectangles = 6 x 5 x 11 = 330 cm

Total surface area = 64.5 + 64. 5+ 330 = 459 cm²

------------------------------------------------------------------------
Answer: Total surface area = 459 cm²
------------------------------------------------------------------------
5 0
3 years ago
The following data summarizes results from 939 pedestrian deaths that were caused by accidents . If one of the pedestrian deaths
olganol [36]

Answer:

Step-by-step explanation:

Hello!

The contingency table is attached.

The total of pedestrians is 909, not 939, there are 30 accidents less in the given data.

I've calculated the asked probabilities using a total of 909.

1. The probability that the pedestrian was intoxicated or the driver was intoxicated.

Two events are mutually exclusive when the occurrence of one prevents the occurrence of the other in one single performance of the experiment. (i.e there is no intersection between the events P(A∩B)=0)

When two events are mutually exclusive, the probability of the union of both elements is equal to the sum of their individual probabilities P(A∪B)= P(A) + P(B).

When the events aren't mutually exclusive, the probability of their union is equal to the summary of their probabilities minus the probability of the intersection between these two events P(A∪B)= P(A) + P(B) - P(A∩B)

Where:

∪ is the union of both events, in colloquial language represents "or"

∩ is the union of both events, or intersection of the events, in colloquial language represents "and"

In this case P(P₁ ∪ D₁) = P(P₁) + P(D₁) - P(P₁ ∩ D₁) = \frac{306}{909} + \frac{132}{909} - \frac{81}{909} = 0.393

P₁ and D₁ are not mutually exclusive

2. The probability of the pedestrian was intoxicated or the driver was not intoxicated.

These two events aren't mutually exclusive.

P(P₁ ∪ D₂)= P(P₁) + P(D₂) - P(P₁ ∩ D₂)= \frac{306}{909} +\frac{777}{909} *-\frac{225}{909}= 0.944

I hope it helps!

3 0
3 years ago
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