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V125BC [204]
3 years ago
10

The reaction that is carried out by the enzyme catalase produces __________. The reaction that is carried out by the enzyme cata

lase produces __________. H2O and CO2 H2O and O2 O2 and CO2 H2O2
Chemistry
1 answer:
Mnenie [13.5K]3 years ago
6 0

Answer:

(a) H_{2}O   (b) CO_{2}

Explanation:

The reaction that is carried out by the enzyme catalase produces H_{2} O

The reaction that is carried out by the enzyme catalase produces CO_{2}

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Which statement is always true about conversation of matter?
Firlakuza [10]

Answer:

The mass of a system does not change during a chemical reaction

Explanation:

Correct Answers

8 0
3 years ago
1. How much 6.0 M HNO3 is needed to neutralize 39 mL of 2.0 M KOH?
quester [9]

Answer:

For 2. the answer is 15.0 mL

For other examples, you can solve by exact way as I have solved the 2nd example.

I have writen down all the balanced chemical reaction equation for examples 1, 3, 4, 5 for you. ( picture 2 )

Explanation:

Please see the step-by-step solution in the picture attached below.(picture 1)

Hope this answer can help you. Have a nice day!

6 0
3 years ago
Determine the number of significant figures in 478 cm​
Grace [21]

Answer:

There are 3 significant figures on this one.

3 0
3 years ago
The following statements all describe changes in matter. Some of these changes are physical, and some are chemical. Select the s
GenaCL600 [577]

The change of the statue of liberty from copper to green is an example of a chemical change.

<h3>Physical and chemical change</h3>

A physical change does not involve the formation of new substances and the composition of the substance does not change. However, in a chemical change, a new substance is formed and the composition of the substance changes.

The statement that reflect a chemical change is;

  • The Statue of Liberty’s metal tarnishes from copper to green.

Learn more about physical and chemical change: brainly.com/question/13316655

8 0
2 years ago
(4) Calculate the % of a compound that can be removed from liquid phase 1 by using ONE to FOUR extractions with a liquid phase 2
maksim [4K]

Answer:

One extraction: 50%

Two extractions: 75%

Three extractions: 87.5%

Four extractions: 93.75%

Explanation:

The following equation relates the fraction q of the compound left in volume V₁ of phase 1 that is extracted n times with volume V₂.

qⁿ = (V₁/(V₁ + KV₂))ⁿ

We also know that V₂ = 1/2(V₁) and K = 2, so these expressions can be substituted into the above equation:

qⁿ = (V₁/(V₁ + 2(1/2V₁))ⁿ = (V₁/(V₁ + V₁))ⁿ =  (V₁/(2V₁))ⁿ = (1/2)ⁿ

When n = 1, q = 1/2, so the fraction removed from phase 1 is also 1/2, or 50%.

When n = 2, q = (1/2)² = 1/4, so the fraction removed from phase 1 is (1 - 1/4) = 3/4 or 75%.

When n = 3, q = (1/2)³ = 1/8, so the fraction removed from phase 1 is (1 - 1/8) = 7/8 or 87.5%.

When n = 4, q = (1/2)⁴ = 1/16, so the fraction removed from phase 1 is (1 - 1/16) = 15/16 or 93.75%.

5 0
3 years ago
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