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3 years ago

How many thirds in 10?

Mathematics

1 answer:

n200080 [17]3 years ago

5 0

Its 30 . hope this helps u

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The boys wrestling team scored a total of 36 points. Pins are worth 6 points. Major

shtirl [24]

Answer:

6p + 4d = 36

Step-by-step explanation:

If p = number of pins and d = number of major decisions, then the equation is 6p + 4d = 36.

Hope this helps!

5 0

3 years ago

PLEASE ANSWER FAST WILL DO BRAINLIESTThe coordinate grid shows points A through K. What point is a solution to the system of ine

Alja [10]

Answer: points B (4,7) and I (9,3)

If the inequalities are

y > −2x + 10 and y> (½)x -2

Step-by-step explanation: If I interpreted the inequalities correctly, the attached graph shows them. It is possible that you meant y > 1/(2x-2) for the second inequality. If so, we start over!

You can test the values for all the points, but it appears that (4,7) and (9,3) both work.

The other coordinates appear to be outside the solution -- the dark-shaded area.

I hope this is your Brainliest answer. It was a lot of work!

4 0

3 years ago

A cylinder and a cone have congruent heights and radii. What is the ratio of the volume of the cone to the volume of the cylinde

n200080 [17]

A cone with the same radius and height as a cylinder will have one-third the volume of the cylinder.

Vcone = (1/3)*π*r^2*h

Vcylinder = π*r^2*h

8 0

3 years ago

(9 x 10 ^10) - ( 4x10^10)

Marianna [84]

Answer:

5 * 10^10

Step-by-step explanation:

that's it bro. learn how to do it. then you won't need brainly anymore foo'.

4 0

3 years ago

Choose one of the factors of 500x3 + 108y18

sammy [17]

Answer:

Option C

Therefore, one of the factors of $500x^3 +108y^\left (18\right )$ is $(5x+3y^6)$ .

Step-by-step explanation:

Given: $500x^3 +108y^\left (18\right )$

the common factor from $500x^3$ and $108y^\left (18\right )$ is 4.

therefore, $4\cdot \left ( 125x^3+27y^\left (18\right ) \right )$

$4\cdot \left ( (5x)^3+(3y^6)^3 \right))$

Now, use the formula for above expression: $(a^3+b^3)=(a+b)(a^2-ab+b^2)$

here, $a=5x$ and $b=3y^6$

$( (5x)^3+(3y^6)^3 \right))$ $=(5x+3y^6)(25x^2-15xy^6+9y^12)$

Therefore, we have

$500x^3 +108y^\left (18\right )$ $=4\cdot (5x+3y^6)\left (25x^2-15xy^6+9y^\left ( 12 \right ) \right )$

Therefore, one of the factors of $500x^3 +108y^\left (18\right )$ is $(5x+3y^6)$ .

7 0

3 years ago

Read 2 more answers