If the covariance is 1225, variance of x is 1600,variance of y is 2500 then the correlation coefficient between x and y is 0.6125.
Given the covariance is 1225, variance of x is 1600,variance of y is 2500.
We have to find the correlation coefficient between x and y.
Covariance is basically a measure of the joint variability of two random variables.
Variance is a basically a measure of dispersion, meaning it is a measure of how far a set of numbers is spread out from their average value.
The correlation coefficient is basically the specific measure that quantifies the strength of the linear relationship between two variables in a correlation analysis.
We know that the formula of correlation coefficient is as under:
r=
r=1225/
r=1225/(40*50)
r=1225/2000
r=0.6125
Hence if the covariance is 1225, variance of x is 1600,variance of y is 2500 then the correlation coefficient between x and y is 0.6125.
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Answer:
495
Step-by-step explanation:
To find this you have to find the LCM of the two times which in this case is 33 and 45. The LCM of those two is 495.
Answer:
34
Step-by-step explanation:
Answer: Choice A
Set the radicand (stuff under the radical) greater than or equal to 0. Solve x+11 >= 0 for x to get x >= -11
Answer:
25 can.
Step-by-step explanation:
Here is the complete question: You are making juice from concentrate. The directions on the packaging say to mix 1 can of juice with 3 cans of water to make orange juice. How many 12 fluid ounces cans of the concentrate are required to prepare 200 6-ounce servings of orange juice?
Given: Ratio to make juice with concentrate:water is 1:3.
As required we need to prepare 200 6 ounce serving of Orange juice.
∴
Let there be x ounce of concentrate and 3x ounce of water to make 1200 ounce of orange juice.
Now,
∴ x= 300 ounce
Next, lets find out how many cans of 12 ounce is required.
∴ 25 cans is required to make 1200 ounce of orange juice.