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HACTEHA [7]
3 years ago
6

Kendra is considering two different long-distance phone plans. Phone plan A charges a $100 sign-up fee and 3 cents per minute. P

hone plan B does not charge a sign-up fee, but it charges 5 cents per minute.
Enter the number of minutes where Kendra will pay the same amount for each long distance phone plan.
Mathematics
1 answer:
Gekata [30.6K]3 years ago
5 0

Answer:

The number of minutes in a month must be equal to 50 minutes

Step-by-step explanation:

Let

x ---> the number of minutes

we have

<em>Cost Plan A</em>

3x+100

<em>Cost Plan B</em>

5x

we know that

In order for plan A cost the same than plan B, the following equation must hold true.

cost of plan A = cost of plan B

substitute

3x+100= 5x

solve for x

5x-3x=100\\2x=100\\x=50\ min

therefore

The number of minutes in a month must be equal to 50 minutes

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AB is tangent to O. If AO = 32 and BC = 98, what is AB? my guess is 130? please help!
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CO = AO  = 32    (Are rays.)
BO = BC + CO = 98 + 32 = 130
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⇒  ΔAOB   is a rectangular triangle.
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\displaystyle\\&#10;AB =  \sqrt{BO^2 - AO^2}  = \sqrt{130^2 -32^2}=\\\\&#10;= \sqrt{16900 -1024}= \sqrt{15876}= \boxed{126 }



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3 years ago
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