To solve letter a:
d1 = 85t1 = 16 km,
85t1 = 16,
t1 = 16 / 85 = 0.1882 h = 11.29 min.
d2 = 115t2 = 16 km,
115t2 = 16,
t2 = 16 / 115 = 0.139 h = 8.35 min.
t1 - t2 = 11.29 - 8.35 = 2.94 min.
Car #2 arrives 2.94 minutes sooner.
To solve letter b:
15 min = 1/4 h = 0.25 h.
d1 = d2,
115t = 85(t + 0.25),
115t = 85t + 21.25,
115t - 85t = 21.25,
30t = 21.25,
t = 21.25 / 30 = 0.71 h,
d = 115 * 0.71 = 81.65 km.
Answer:
Explanation:
electronic configuration of an atom is the spatial arrangement of the electrons around the nucleus in the energy orbits
We know that the atomic number of Titanium is 22
The electronic configuration of Titanium is
Answer:
20.62361 rad/s
489.81804 J
Explanation:
= Initial moment of inertia = 9.3 kgm²
= Final moment of inertia = 5.1 kgm²
= Initial angular speed = 1.8 rev/s
= Final angular speed
As the angular momentum of the system is conserved
The resulting angular speed of the platform is 20.62361 rad/s
Change in kinetic energy is given by
The change in kinetic energy of the system is 489.81804 J
As the work was done to move the weight in there was an increase in kinetic energy
amount of work done is 5880 J
Given:
mass of object = 50kg
Final height = 20m
initial height = 8m
To Find:
amount of work done
Solution:
work is done when a force acts upon an object to cause a displacement. You can calculate the energy transferred, or work done, by multiplying the force by the distance moved in the direction of the force.
The work done by gravity is given by the formula,
W = mgh
W = 50 x 9.8 x ( 20-8)
= 5880 J
So the work done is 5880 J
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The correct answer is y=-2x+(1/2)
y = f'(x)· x + c
Y = -2x + C
1 = -2x π/4 + C
=) C = I + π/2
y=-2x+(1/2) is the first-degree polynomial.
First-degree polynomials are the simplest polynomials. Here, we'll talk about a few qualities and connect the terms polynomial, function, and equation. Write a polynomial equation in standard form before attempting to solve it. Factor it, then set each variable factor to zero after it has reached zero. The original equations' answers are the solutions to the derived equations. Factoring cannot always be used to solve polynomial equations. For instance, the polynomial 2x+5 has an exponent of 1. The most typical kinds of polynomials used in algebra and precalculus are zero polynomial functions.
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