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aleksandrvk [35]
3 years ago
5

A skydiver prepares to jump out of a plane. Explain how gravity and air resistance will affect the motion of the skydiver before

and after he or she opens the parachute.
Physics
2 answers:
jolli1 [7]3 years ago
4 0

Explanation :

When a skydiver prepares to jump out of the plane. Then two forces will acts i.e. the force of gravity and frictional force. Both forces act in the opposite direction.

When the person starts accelerating towards the earth, the gravitational force is stronger.

When he opens the parachute, the surface area increases and hence the resistive force increase. As a result, he or she attains the terminal velocity.

ahrayia [7]3 years ago
3 0
Before the skydiver opens the parachute, his velocity would be increasing greatly as much as 9.8 m/s². Opening the parachute would increase the surface area to which air may cause resistance. The skydiver then reaches his terminal velocity. 
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Answer:

La distancia entre los dos cuerpos es aproximadamente 1.269 milímetros.

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Asumamos que ambos cuerpos son partículas, la fuerza de atracción (F), en newtons, entre ambos cuerpos se define mediante la Ley de Newton de la Gravitación Universal, cuya ecuación es:

F = G \cdot \frac{m_{1}\cdot m_{2}}{r^{2}} (1)

Donde:

G - Constante de la gravitación universal, en metros cúbicos por kilogramo-segundo cuadrado.

m_{1}, m_{2} - Masas de los cuerpos, en kilogramos.

r - Distancia entre los cuerpos, en metros.

Si sabemos que G = 6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}}, m_{1} = 0.48\,kg, m_{2} = 0.196\,kg y F = 3.9\times 10^{-6}\,N, entonces la distancia entre los dos cuerpos es:

r = \sqrt{\frac{G\cdot m_{1}\cdot m_{2}}{F} }

r \approx 1.269\times 10^{-3}\,m

Es decir, la distancia entre los dos cuerpos es aproximadamente 1.269 milímetros.

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