Answer:
salt water, air and vinegar are homogeneous solutions.
Explanation:
A solution which consists of particles of same proportion is known as a homogeneous solution. Whereas a solution which consists of particles of different proportion is known as a heterogeneous solution.
Salt and water are homogeneous solutions as salt completely disperses in water and forms a clear solution as the particles of salt and water are in proportion.
Air is composed of different gases like nitrogen, oxygen etc are all mixed in fixed ratio. Therefore, air is a homogeneous mixture.
Sand and water are heterogeneous solution as the ration of mixing is different and more over sand particles can be separated from water. Thus, it is not a homogeneous mixture.
Vinegar is also a homogeneous solution as it is composed of acetic acid and water which are mixed in fixed proportion.
Cement is a heterogeneous mixture as it is composed of a number of different substances mixed in different proportions.
Thus, we can conclude that salt water, air and vinegar are homogeneous solutions.
Most directly on equador and least directly at poluses
Galaxy million of star and planet. gravitional wave field all the universe some planet explosive itself moving other places . Black holes Mass gravity field
Answer:
The answer for the above statement is:
C. High-visibility clothing is important to wear in areas with moving vehicles.
because in bright clothes you are easier to see, so people driving can see you.
Explanation:
Answer:
The minimum frequency is 702.22 Hz
Explanation:
The two speakers are adjusted as attached in the figure. From the given data we know that
=3m
=4m
By Pythagoras theorem

Now
The intensity at O when both speakers are on is given by

Here
- I is the intensity at O when both speakers are on which is given as 6

- I1 is the intensity of one speaker on which is 6

- δ is the Path difference which is given as

- λ is wavelength which is given as

Here
v is the speed of sound which is 320 m/s.
f is the frequency of the sound which is to be calculated.

where k=0,1,2
for minimum frequency
, k=1

So the minimum frequency is 702.22 Hz