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Norma-Jean [14]
3 years ago
6

A train accelerated from 5 km/hr in 0.5 hours. what was the rate of acceleration?

Physics
1 answer:
Bezzdna [24]3 years ago
5 0
Acceleration is the simply rate of change in velocity, how much faster or slower is the object changing speed with respect to time.

A = v/t = 5 km/hr/0.5 hr

5/1/2 = 5 • 2 = 10 km/hr^2.

This would be the acceleration.
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Which statement best define energy
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Answer:

"The capacity of a system to perform work of any type."

Explanation:

The best statement to describe Energy is:

"The capacity of a system to perform work of any type."

6 0
4 years ago
A person, with his ear to the ground, sees a huge stone strike the concrete pavement. A moment later two sounds are heard from t
VladimirAG [237]

Answer:

271.095 m

Explanation:

✓ Let speed of sound in air that was given as (343 m/s) be represented as (Vi)

✓( speed of sound in concrete that was given as (3000 m/s ) be debited as (Vc)

✓ Let the distance travelled by the sound = s

✓duration of Time that exist between heard of sounds = 0.70s

But we know that

Time = (Distance / Speed)

✓Time it takes the sound to travel through air= s/vi = s/343

✓Time it takes the sound to travel through concrete= s/vc = s/3000

✓ (s/343) - (s/3000) = 0.70

Finding LCM and simplify

[(3000s - 343s)]/1029000 = 0.70

2657s /1029000 = 0.70

Making " s" subject of the formula

s= (1029000 × 0.70)/2657

s=720300/ 2657

s= 271.095 m

Hence, The impact took place at a distance of 271.095 m away from the person.

4 0
3 years ago
Please help with some/all questions on this worksheet
Roman55 [17]
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5 0
2 years ago
PLSSSS Jenny runs every morning for exercise she takes 25 minutes to run 1,000 m and walk 1,600 m or 20 minutes to run 2,000 m a
ELEN [110]

The running speed of Jenny willl be 2.5 times the velocity she walks.

<h3 /><h3>What is velocity?</h3>

The change of distance concerning to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

Condition 1;

She takes 25 minutes to run 1,000 m and walk 1,600 m The total time to run as well as the walk is 25 minutes.

\rm  t = t_r +t_w \\\\ 25 =  t_r +t_w

As we know that;

Distance = speed × time

\rm x_r = v_r \times t_r \\\\ t_r = \frac{x_r}{v_r}

For walking;

\rm t_w = \frac{x_w}{v_w}

\rm  t = t_r +t_w \\\\ 25 = \frac{x_r}{v_r} +\frac{x_w}{v_w} \\\\  25 = \frac{1000 \ m}{v_r} +\frac{1600 \ }{v_w} \\\\ 40 v_w +64 v_r = v_rv_w

Same as for condition 2;

\rm 100 v_w + 40 v_r = v_rv_w

\rm 40 v_w +64 v_r =\rm 100 v_w + 40 v_r \\\\ v_r = 2.5 v_w

Condition 3;

\rm d_w = 800 \ m

\rm d_w = v_w \times t_w

\rm t_w  = \frac{d_w}{v_w } \\\\ \rm t_w  = \frac{800}{v_w } \\\\

Hence their running speed of Jenny willl be 2.5 times the velocity at she walks.

To learn more about the velocity, refer to the link: brainly.com/question/862972.

#SPJ1

5 0
2 years ago
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