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3 years ago

A train accelerated from 5 km/hr in 0.5 hours. what was the rate of acceleration?

1 answer:

5 0

Acceleration is the simply rate of change in velocity, how much faster or slower is the object changing speed with respect to time.

A = v/t = 5 km/hr/0.5 hr

5/1/2 = 5 • 2 = 10 km/hr^2.

This would be the acceleration.

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What is her velocity

fenix001 [56]

The speed of something in any given direction.

7 0

2 years ago

Explain any 3 alternating ways of producing electricity

ehidna [41]

Answer:

to produce electricty three ways you have the water wheel the wind mill and solor panels

Explanation:

4 0

2 years ago

A solenoidal coil with 26 turns of wire is wound tightly around another coil with 350 turns. The inner solenoid is 20.0 cm long

noname [10]

Answer:

Part a)

$\phi = 2.76 \times 10^{-7} T m^2$

Part B)

$M = 5.52 \times 10^{-5} H$

Part C)

$EMF = 0.1 V/s$

Explanation:

Part a)

Magnetic field due to a long ideal solenoid is given by

$B = \mu_0 n i$

n = number of turns per unit length

$n = \frac{N}{L}$

$n = \frac{350}{0.20}$

$n = 1750 turn/m$

now we know that magnetic field due to solenoid is

$B = (4\pi \times 10^{-7})(1750)(0.100)$

$B = 2.2 \times 10^{-4} T$

Now magnetic flux due to this magnetic field is given by

$\phi = B.A$

$\phi = (2.2 \times 10^{-4})(\pi r^2)$

$\phi = (2.2 \times 10^{-4})(\pi(0.02)^2)$

$\phi = 2.76 \times 10^{-7} T m^2$

Part B)

Now for mutual inductance we know that

$\phi_{total} = M i$

$\phi_{total} = N\phi$

$\phi_{total} = 20(2.76 \times 10^{-4})$

$\phi_{total} = 5.52 \times 10^{-6}$

now we have

$M = \frac{5.52 \times 10^{-6}}{0.100}$

$M = 5.52 \times 10^{-5} H$

Part C)

As we know that induced EMF is given as

$EMF = M \frac{di}{dt}$

$EMF = 5.52 \times 10^{-5} (1800)$

$EMF = 0.1 V/s$

3 0

3 years ago

A dart leaves a toy dart gun with initial velocity of 7.76 m/s, regardless of the angle it is fired. What is the maximum horizon

In-s [12.5K]

Vf=vi plus 2 ad
0=7.76 + 2(9.8)d
d=0.395m

4 0

3 years ago

Coherent monochromatic light of wavelength l passes through a narrow slit of width a, and a diffraction pattern is observed on a

geniusboy [140]

Answer:

λ = a

Explanation:

This is a diffraction exercise that is described by the expression

a sin θ = m λ

sin θ = m λ/ a

the first zero of the diffraction occurs for m = 1

sin θ = λ / a

angles are generally very small and are measured in radians

sin θ = θ = y / x

we substitute

$\frac{y}{x} = \frac{\lambda}{a}$

the width of the central maximum is twice the distance to zero

w = 2y

in the exercise indicate that this width is equal to twice the distance to the screen (2x)

W = 2x

2y = 2x

we substitute

1 = λ/ a

λ = a

we see that the width of the slit is equal to the wavelength used.

3 0

3 years ago