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Elodia [21]
3 years ago
7

Fair rickets for 2 adults and 3 children cost $34. An adult ticket costs $2 more than a child ticket. What is the price of an ad

ult ticket
Mathematics
2 answers:
Jobisdone [24]3 years ago
8 0

Answer:

Childs ticket = $6

6+2=8

Adult's ticket = $8

Step-by-step explanation:


kogti [31]3 years ago
3 0

Answer:

solving for x

        $6 , the cost of the child ticket.  Adult ticket is $8  

So your answer is $8!!

Hope this was right and hope it helped!!



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Can someone please answer this question please answer it correctly and lease show work please help me I need it
earnstyle [38]

Answer:

C

Step-by-step explanation:

The correct answer would be \frac{-5}{3}.  Therefore, none of the answer choices fulfill this and A and B are not correct.

8 0
3 years ago
Read 2 more answers
Is it A? If not, why?
Lostsunrise [7]

Answer:

It's A 7^7

Step-by-step explanation:

This is because if two numbers with the same base divide,we subtract the exponent of the divisor from that of the dividend

8 0
2 years ago
A confidence interval was used to estimate the proportion of statistics students that are female. A random sample of 72 statisti
jeyben [28]

Answer:

We need a sample of size at least 13.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

90% confidence interval: (0.438, 0.642).

The proportion estimate is the halfway point of these two bounds. So

\pi = \frac{0.438 + 0.642}{2} = 0.54

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Using the information above, what size sample would be necessary if we wanted to estimate the true proportion to within ±0.08 using 95% confidence?

We need a sample of size at least n.

n is found when M = 0.08. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.08 = 1.96\sqrt{\frac{0.54*0.46}{n}}

0.08\sqrt{n} = 1.96\sqrt{0.54*0.46}

\sqrt{n} = \frac{1.96\sqrt{0.54*0.46}}{0.08}

(\sqrt{n})^{2} = (\frac{1.96\sqrt{0.54*0.46}}{0.08})^{2}

n = 12.21

Rounding up

We need a sample of size at least 13.

3 0
3 years ago
What does the graph of an equation reveal about the solutions to the equation?
Triss [41]
It reveals whether the answers will be negative, and how many solutions the equation will have. 
3 0
3 years ago
For f(x) = 2x + 1 find each value. <br> f(6) <br> f(3) <br> f(−5)
sertanlavr [38]
F(6) = 2(6) + 1
= 12 +1
= 13

f(3) = 2(3) + 1
= 6 + 1
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f(-5) = 2(-5) + 1
= -10 + 1
= -9
7 0
2 years ago
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