Answer:
Those with 3 protons and 3 neutrons are known as the isotope lithium-6. Those with 3 protons and 4 neutrons are known as the isotope lithium-7.
Explanation:
The enthalpy change of the reaction below (ΔHr×n , in kJ) using the bond energies provided. CO(g) + Cl₂(g) → Cl₂CO(g). is - 108kJ.
The bond energies data is given as follows:
BE for C≡O = 1072 kJ/mol
BE for Cl-Cl = 242 kJ/mol
BE for C-Cl = 328 kJ/mol
BE for C=O = 766 kJ/mol
The enthalpy change for the reaction is given as :
ΔHr×n = ∑H reactant bond - ∑H product bond
ΔHr×n = ( BE C≡O + BE Cl-Cl) - ( BE C=O + BE 2 × Cl-Cl )
ΔHr×n = ( 1072 + 242 ) - ( 766 + 656 )
ΔHr×n = 1314 - 1422
ΔHr×n = - 108 kJ
Thus, The enthalpy change of the reaction below ( ΔHr×n , in kJ) using the bond energies provided. CO(g) + Cl₂(g) → Cl₂CO(g). is - 108kJ.
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When water is added to a compound in a chemical equation, a new compound can be formed, it is called a hydrolysis reaction.
<h3>What is hydrolysis reaction?</h3>
There are so many kinds of reaction in chemistry we know that a chemical reaction occurs between reactant molecules in order to yield products in the reactants.
The hydrolysis reaction is a breaking up reaction. In a hydrolysis reaction, water is used to break up a molecule. Hence in a hydrolysis reaction water could be regarded as one of the reactants in the reactions going on in the system.
We know that a hydrolysis is a reaction in which water reacts with another reactant molecule to yield products in the reaction. Thus, when water is added to a compound in a chemical equation, a new compound can be formed, it is called a hydrolysis reaction.
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Answer:
Explanation:
If the concentration of any substance A in a dynamic equilibrium increases, The equilibrium will be shifted to its opposite side so that Substance A can be created less and the substance opposite to A can be created more so that a "dynamic equilibrium" can again be established.
