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umka2103 [35]
4 years ago
13

How many moles of O2 will be formed from 1.65 moles of KCIO3? (2KClO3–>2KCl + 3O2)

Chemistry
1 answer:
Oduvanchick [21]4 years ago
7 0

Answer:

2.475 mol of O2  formed.

Explanation:

Given 1.65 moles of KClO3 as the target amount in the reactant, used the coefficient of the balanced chemical reaction involved to determine the number of moles of O2 molecules formed.

x mole of  O2   = 1.65 mol  KClO3 x [(3 mol O2)/ (2 mol KClO3)] = 2.475 mol of O2

x mole of  O2 formed  = 2.475 mol of O2

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Answer:

6.22 × 10⁻⁵

Explanation:

Step 1: Write the dissociation reaction

HC₆H₅COO ⇄ C₆H₅COO⁻ + H⁺

Step 2: Calculate the concentration of H⁺

The pH of the solution is 2.78.

pH = -log [H⁺]

[H⁺] = antilog -pH = antilog -2.78 = 1.66 × 10⁻³ M

Step 3: Calculate the molar concentration of the benzoic acid

We will use the following expression.

Ca = mass HC₆H₅COO/molar mass HC₆H₅COO × liters of solution

Ca = 0.541 g/(122.12 g/mol) × 0.100 L = 0.0443 M

Step 4: Calculate the acid dissociation constant (Ka) for benzoic acid

We will use the following expression.

Ka = [H⁺]²/Ca

Ka = (1.66 × 10⁻³)²/0.0443 = 6.22 × 10⁻⁵

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