In this question, XB3(aq) is an ionic compound which will have the releasing of 3 B⁻ ions ions in water for every molecule of XB3 that dissolves.
XB3(s) --> X+(aq) + 3 B⁻(aq)
[B⁻] = 0.22 mol XB3/1L × 3 mol B⁻ / 1 mol XB3 = 0.66 M
The answer to this question is [B⁻] = 0.66 M
Answer:
the solvent is water and the solute is salt
Explanation:
A solute is the component in a solution in the lesser amount. In a NaCl solution, the salt is the solute. A solution may contain more than one solute.
Answer:
32.3 dm³
Explanation:
Data given:
no. of molecules of Cl₂ = 8.7 x 10²³
Volume of chlorine gas (Cl₂) = ?
Solution:
First we have to find number of moles
For this formula used
no. of moles = no. of molecules / Avogadros number
no. of moles = 8.7 x 10²³ / 6.022 x 10²³
no. of moles = 1.44 moles
Now we have to find volume of the gas
for this formula used
no. of moles = volume of gas / molar volume
molar volume = 22.4 dm³/mol
Put values in above equation
1.44 moles = volume of Cl₂ gas / 22.4 dm³/mol
rearrange the above equation
volume of Cl₂ gas = 1.44 moles x 22.4 dm³/mol
volume of Cl₂ gas = 32.3 dm³
Answer:
intermolecular dipole-dipole hydrogen bonds
Explanation:
Water is a polar molecule. Recall that the central atom in water is oxygen. The molecule is bent, hence it has an overall dipole moment directed towards the oxygen atom. Since it has a permanent dipole moment, we expect that it will show dipole-dipole interactions in the liquid state.
Similarly, water contains hydrogen and oxygen. Recall that hydrogen bonds are formed when hydrogen is covalently bonded to highly electronegative elements. Hence, water in the liquid state exhibits strong hydrogen bonding. The unique type of dipole-dipole interaction in liquid water is actually hydrogen bonding, hence the answer.
The correct answer is the statement in option 3. Chemical equilibrium is achieved when both the reactants and the products are in concentrations that has no further tendency to change even as time goes to infinity. This happens when the forward reaction rate is the same as the reverse reaction rate.
