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joja [24]
2 years ago
14

What is the molar mass of sulfur trioxide?

Chemistry
2 answers:
julia-pushkina [17]2 years ago
8 0

Answer:

80.07 g/mol

Explanation:

tatyana61 [14]2 years ago
6 0

Answer:

80.07 g/mol

Explanation:

Sulfur's g/mol = 32.07

Oxygen's g/mol = 16.00

32.07 + 16.00(3) = 80.07 g/mol

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g Phosphorus -32 is a commonly used radioactive nuclide in biochemical research, particularly in studies of nucleic acids. The h
Setler79 [48]

Answer:

6.88 mg

Explanation:

Step 1: Calculate the mass of ³²P in 175 mg of Na₃³²PO₄

The mass ratio of Na₃³²PO₄ to ³²P is 148.91:31.97.

175 mg g Na₃³²PO₄ × 31.97 g ³²P/148.91 g Na₃³²PO₄ = 37.6 mg ³²P

Step 2: Calculate the rate constant for the decay of ³²P

The half-life (t1/2) is 14.3 days. We can calculate k using the following expression.

k = ln2/ t1/2 = ln2 / 14.3 d = 0.0485 d⁻¹

Step 3: Calculate the amount of P, given the initial amount (P₀) is 37.6 mg and the time elapsed (t) is 35.0 days

For first-order kinetics, we will use the following expression.

ln P = ln P₀ - k × t

ln P = ln 37.6 mg - 0.0485 d⁻¹ × 35.0 d

P = 6.88 mg

3 0
2 years ago
3. Given the reaction:
sesenic [268]

Answer:

Attached

Explanation:

3 0
2 years ago
A rectangular block of solid carbon (graphite) floats at the interface of two immiscible liquids.
Sergio039 [100]

Explanation:

Let us take the volume of block is x.

Since, the block is floating this means that it is in equilibrium. Formula to calculate net force will be as follows.

                F_{net} = Buoyancy force(F_{b}) - weight force(w)

Also, buoyancy force (F_{b}) = (volume submerged in water × density of water) + (volume in oil × density of oil)

          (F_{b}) = (0.592 V \times \rho) + (1 - 0.592)V \times 1000 g          

                      = (0.592 V \times \rho + 408 V) g

As,   W = V × density of graphite × g

It is given that density of graphite is 2.16 g/cm^{3} or 2160 kg/m^{3}.

So, W = 2160 V g

F_{net} = (0.592 V \rho + 408 V) g - 2160 V g = 0

            0.592 \rho = 1752

     \rho = 2959.46 kg/m^{3} or 2.959 g/cm^{3} is the density of oil.

It is given that mass of flask is 124.8 g.

Mass of 35.3 cm^{3} oil = 35.3 \times 2.959 104.7 g

Hence, in second weighing total mass will be calculated as follows.

                       (124.8 + 104.7) g

                       = 229.27 g

Thus, we can conclude that in the second weighing mass is 229.27 g.

5 0
2 years ago
Why do lithium (Li) and sodium (Na) have similar properties?
ella [17]
B, they belong to group 1

A: Li is period 2 and Na is period 3

C: Na has one more electron shell

D: Not related to how it is spelled
8 0
2 years ago
A teacher moves a box of books weighting 25lbs a distance of 40ft. How much work has she done?
svp [43]

Answer:

workdone = weight \:  \times  \: distance \\  = 25 \times 40 \\  = 1000 \: lbsft \\ or \\  = 1000 \: joules

6 0
3 years ago
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