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3 years ago

If a wall is in a 1/4 in scale drawing is 6 in tall how tall is the actual wall

1 answer:

6 0

So 1/4
that measn that the scale wall is 6 inches while the real wall is 4 times 6=24 inches tall (logically, it would be something like 1in/4ft so it woul dbe 24 feet not 24 inches but ok)

so 1/4
6 inches scale drawing is 1/4 of real wall
6=1/4 real
multiply by 4
24=real

asnwer is 24 inches

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What is the measure of n?<br> 12<br> 4<br> n<br> m

Solnce55 [7]

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3 0

2 years ago

Carla is collecting rainwater in a barrel. Currently she has 18 inches of water in the barrel. The rain is falling at the rate o

olga_2 [115]

Answer: it will take 9 hours.

Step-by-step explanation:

The rain is falling at the rate of 1.5 inches per hour. This means that the height of water in the barrel is increasing in arithmetic progression.

The formula for determining the nth term of an arithmetic sequence is expressed as

Tn = a + d(n - 1)

Where

a represents the first term of the sequence.

d represents the common difference.

n represents the number of terms in the sequence.

From the information given,

a = 18 inches

d = 1.5 inches

The expression becomes

Tn = 18 + 1.5(n - 1)

For the number of hours it would take to collect 30 inches of rain in the barrel, Tn = 30

Therefore,

30 = 18 + 1.5(n - 1)

1.5(n - 1) = 30 - 18

1.5(n - 1) = 12

n - 1 = 12/1.5 = 8

n = 8 + 1

n = 9

6 0

3 years ago

the production of a printer consists of the cost of raw material at 100 dollars the cost of overheads at 80$ and wages at 120$ i

Vadim26 [7]

Answer:

The percentage increase in the production cost of the printer is 3%.

Step-by-step explanation:

We are given that the production of a printer consists of the cost of raw material at 100 dollars the cost of overheads at 80$ and wages at 120$.

Also, the cost of raw materials and overheads are increased by 11% and 20% respectively while wages are decreased by 15%.

Cost of raw material = $100

Cost of overheads = $80

Cost of wages = $120

So, the total cost of the printer = $100 + $80 + $120

= $300

Now, the increase in the cost of raw material = $100 + 11% of $100

= $\$100 + (\frac{11}{100} \times \$100)$

= $100 + $11 = $111

The increase in the cost of overheads = $80 + 20% of $80

= $\$80 + (\frac{20}{100} \times \$80)$

= $80 + $16 = $96

The decrease in the cost of wages = $120 - 15% of $120

= $\$120 - (\frac{15}{100} \times \$120)$

= $120 - $18 = $102

So, the new cost of a printer = $111 + $96 + $102 = $309

Now, the percentage increase in the production cost of the printer is given by;

% increase = $\frac{\text{Net increase in the cost of printer}}{\text{Original cost of printer}} \times 100$

= $\frac{\$309- \$300}{\$300} \times 100$

= 3%

Hence, the percentage increase in the production cost of the printer is 3%.

4 0

3 years ago

Based on historical data, your manager believes that 37% of the company's orders come from first-time customers. A random sample

fomenos

Answer:

0.6214 = 62.14% probability that the sample proportion is between 0.26 and 0.38

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$