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soldier1979 [14.2K]
3 years ago
12

Which transformation can verify congruence by sliding one triangle over another

Mathematics
2 answers:
lions [1.4K]3 years ago
6 0
The answer would be A. Translation. Hope this helps! :)
Paha777 [63]3 years ago
3 0
Translation is the sliding of one triangle over another
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Pls answer I will give brainliest
Levart [38]

Answer: 108 ft³ 

Step-by-step explanation:

V= 4/3πr³ 

Facts:

Pi= 3

Diameter = 6

Step1; find the radius

Diameter is the length acaross the whole circle, but the radius is just 1/2 the circle. Therefore, if the diameter is 6, then the radius can be found by finding 1/2 of 6.

1/2 of 6= 1/2x6= 3.

R= 3

Step 2:  Plug in the numbers (into the formula)

PEMDAS

(exponents go first)

(then multiply from left to right)

V= 4/3πr³ 

V= 4/3x3x3³ 

V= 4/3x3x (3x3x3)

V= 4/3x3x27

V= (4/3x3)  x 27

V= 12/3x27

V= 4x27

V= 108

<u><em>Volume= 108 ft³ </em></u>

<u><em></em></u>

Hope this helps :)) Also brainliest would be appreciated, i worked pretty hard on this thanks! :)

7 0
2 years ago
Read 2 more answers
the half-life of chromium-51 is 38 days. If the sample contained 510 grams. How much would remain after 1 year?​
madam [21]

Answer:

About 0.6548 grams will be remaining.  

Step-by-step explanation:

We can write an exponential function to model the situation. The standard exponential function is:

f(t)=a(r)^t

The original sample contained 510 grams. So, a = 510.

Each half-life, the amount decreases by half. So, r = 1/2.

For t, since one half-life occurs every 38 days, we can substitute t/38 for t, where t is the time in days.

Therefore, our function is:

\displaystyle f(t)=510\Big(\frac{1}{2}\Big)^{t/38}

One year has 365 days.

Therefore, the amount remaining after one year will be:

\displaystyle f(365)=510\Big(\frac{1}{2}\Big)^{365/38}\approx0.6548

About 0.6548 grams will be remaining.  

Alternatively, we can use the standard exponential growth/decay function modeled by:

f(t)=Ce^{kt}

The starting sample is 510. So, C = 510.

After one half-life (38 days), the remaining amount will be 255. Therefore:

255=510e^{38k}

Solving for k:

\displaystyle \frac{1}{2}=e^{38k}\Rightarrow k=\frac{1}{38}\ln\Big(\frac{1}{2}\Big)

Thus, our function is:

f(t)=510e^{t\ln(.5)/38}

Then after one year or 365 days, the amount remaining will be about:

f(365)=510e^{365\ln(.5)/38}\approx 0.6548

5 0
2 years ago
WILL GIVE BRAINLIEST PLZ HURRY!!!!!!!!Woodland High School recently won the state Academic Bowl Championship. The medal counts f
Maru [420]

Answer: B = The range is greater than the mean.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Lucy will rent a car for the weekend. She can choose one of two plans. The first plan has an initial fee of $53 and costs an add
Alchen [17]

Answer:

The amount driven would be 275, and the cost for both plans will be 77.75$

Step-by-step explanation:

make both equations

y=0.09x+53

y=0.13x+42

set them equal to each other and solve for x to get the distance

take that number and put it in one equation and solve for y to get the price of the plan for that value

6 0
2 years ago
Adding and subtracing linear wxpressions 12(−4x+8)−14(8x−12)
Delicious77 [7]

Answer:

-160x+264

Step-by-step explanation:

-48+96x-112x+168

-160+264

3 0
3 years ago
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