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Serhud [2]
3 years ago
6

Two girls are standing on a rollerskates holding a basketball. One girl throws the ball to the other. Explain what happens to th

e girls with references to newton's third law of motion
Physics
1 answer:
katovenus [111]3 years ago
6 0

Answer:

Pretty sure that the they both go backwards because of the basketballs motion

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Danny Diver weighs 500 N and steps off a diving board 10 m above the water. Danny hits the water with kinetic energy of
Morgarella [4.7K]

Answer:

Danny hits the water with kinetic energy of 5000 J.

Explanation:

Given that,

The Weight of Danny Diver,

F = 500 N

m*g= 500 N

He steps off a diving board 10 m above the water.

h=10 m

when Danny diver hits water he generates the kinetic energy.

We need to find the kinetic energy of the water.

Let kinetic energy is K.

K = m*g*h

Where g is acceleration due to gravity.

that g= 9.8 m/s^2

now substituting the values in above equation

K= (500) * 10

K= 5000 J

Hence,

he hits the water with kinetic energy of 5000 J.

Learn more about Kinetic energy here:

<u>brainly.com/question/15587458</u>

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7 0
2 years ago
7. A 2.0 kg block, starting from rest, is pushed by a
11Alexandr11 [23.1K]

Answer:

(A) 0.8 kgm/s

Explanation:

because of the even ground it would only slow down

7 0
3 years ago
Elle is playing with a ball in a bus that moves in a straight line with constant velocity. What can you say about the motion of
kramer
Given that they are all on the same bus that is travelling in a straight line at the same velocity, when Elle throws the ball directly upwards, the ball will simply fall back to her. This is because the bus, Elle, and the ball are all travelling in the same direction and at the same speed. Among the choices, the correct answer is A.
8 0
3 years ago
The most effective way to process biodiversity is through
lidiya [134]
I suppose it's C. All the other answers are everything but accurate to me
6 0
3 years ago
A 1230 kg pile driver is used to drive a steel I-beam into the ground. The pile driver falls 7.07 m before contacting the beam,
PilotLPTM [1.2K]

Answer:

F_{avg} = 5.48 \times 10^5 N

Explanation:

As we know that initial and final speed of the beam is zero

so we can use energy conservation here to find the applied force

So we will have

work done by all the forces = change in kinetic energy of the beam

so we will have

W_g + W_{beam} = \Delta K

mg(L + x) - F_{avg} x = 0

1230(9.81)(7.07 + 0.159) = F_{avg} (0.159)

so we will have

87227.3 = F_{avg} (0.159)

F_{avg} = 5.48 \times 10^5 N

4 0
4 years ago
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