For parts A, B, C, and D you most likely created a line. What question E is asking is for you to create a line that is perpendicular to the line you already created that also passes through the point (1,1). What is important to understand here is that the slope of the perpendicular line is the negative reciprocal of the original line's slope... if the original slope is (-4/3) than the perpendicular slope is (3/4)... then you should just plug that new slope into point-slope form or slope-intercept form to get your equation... y-y1 = m(x-x1) ... y-1= (3/4)(x-1) ... so it would be y=(3/4)x + 1/4 then for part f just convert into standard form which is just manipulating the variables... look up standard form equation on Google and manipulate the variables from there.
Answer:
f(4) = 24
Step-by-step explanation:
Plug in 4 for x in the equation:
f(x) = x² + 3x - 4
f(4) = (4)² + 3(4) - 4
Remember to follow PEMDAS. PEMDAS =
Parenthesis
Exponents (& Roots)
Multiplication
Division
Addition
Subtraction
and is the order of operation.
First, solve the power:
(4)² = 4 * 4 = 16
Next, multiply 3 with 4:
3 * 4 = 12
Next, combine the terms:
f(4) = 16 + 12 - 4
f(4) = (16 + 12) - 4
f(4) = 28 - 4
f(4) = 24
f(4) = 24 is your answer.
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Answer: C
<u>Step-by-step explanation:</u>
The general form of the equation is: g(x) = a|x - h| + k ;
- "a" represents the vertical stretch <em>(or shrink)</em>
- "h" represents the x-coordinate of the vertex (left and right)
- "k" represents the y-coordinate of the vertex (up and down)
4 units left means h = 4
2 units up means k = 2
--> g(x) = |x - 4| + 2
