How many brothers does everyone here have?
Answer:
x *2 + (28-x)*4 = 100
Step-by-step explanation:
Given
Total number of questions in the paper = 28
Out of these 28 questions let us say that x number of questions are of 2 points and 28-x questions are of 4 points.
Also, the complete test is of 100 marks
Thus, the linear equation representing the
x *2 + (28-x)*4 = 100
Since the slope and the y-intercept for the equation of y = mx + b doesn't exist, you don't need to include it.
y = mx + b
Without the m and b, which are the slope and y-intercept, you are left with x.
Then, you need to figure out whether the line is horizontal, or vertical.
If the line is vertical, you keep the x, and find out the value x is on for every point of y.
If the line is horizontal, you keep the y, and find out the value y is on for every point of x.
Since the line is vertical, we can use x = ?
The line is always at x=2, no matter what the y-value is, so the final equation would be x=2.
<em>I hope this helped you! :)</em>
Step-by-step explanation:
if the 2 matrices are inverse, then their product must be the identity matrix
1 0
0 1
so,
m×3 + 2×-7 = 1
7×3 + 3×-7 = 0
m×-2 + 2×m = 0
7×-2 + 3×m = 1
that means we have to solve only
3m - 14 = 1
3m = 15
m = 5
Answer:
In 6 different ways can the three students form a set of class officers.
Step-by-step explanation:
There are 3 people Leila, Larry, and Cindy and 3 positions president, vice-president, and secretary.
We need to find In how many different ways can the three students form a set of class officers.
This problem can be solved using Permutation.
nPr = n!/(n-r)! is the formula.
Here n = 3 and r =3
So, 3P3 = 3!/(3-3)!
3P3 = 3!/1
3P3 = 3*2*1/1
3P3 = 6
So, in 6 different ways can the three students form a set of class officers.
