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liubo4ka [24]
3 years ago
15

Simplify -12u + 11z “Enter the original expression if it cannot be simplified”

Mathematics
1 answer:
jeka943 years ago
6 0

Answer:

-12u + 11z

Step-by-step explanation:

The above expression cannot be simplified, for:

1) There is no common variable (one being <em>u</em>, and the other being <em>z</em>).

2) There are no common factors in between 12 & 11)

 - Factors of 12: 1, 2, 3, 4, 6, 12

 - Factors of 11: 1, 11

~

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Which is the highest value? 1/100, 1/400,1/500
NNADVOKAT [17]
1/100, 1/400, 1/500

Because the numerators are the same, we just need to compare the denominators.

100< 400< 500
⇒ 1/100 > 1/400 > 1/500

Therefore, the highest value is 1/100.

Hope this helps.


3 0
3 years ago
Read 2 more answers
ASAP! GIVING BRAINLIEST! Please read the question THEN answer correctly! No guessing. Show your work or give an explaination.
lozanna [386]

Answer:

D

Step-by-step explanation:

Look at the graph. You want to see how much distance he is at 9 minutes. Go all the way to 9 minutes, then go up. What coordinate does it fall in? (9,80). He travelled 80 meters in 9 minutes. (D)

6 0
3 years ago
To celebrate the first day of winter, Lin was putting stickers on some of the lockers. There are 100 lockers along one side of h
loris [4]

Answer:

<em>24, 48, 72, 96</em>

Step-by-step explanation:

<u>Least Common Multiple (LCM)</u>

It's the smallest positive number that is a multiple of two or more numbers. For example, let's find the LCM of 15 and 25:

Multiples of 15: 15,30,45,60,75,90,...

Multiples of 25: 25,50,75,100,...

Note 75 is a common multiple of both and is also the smallest possible.

Lin puts a snowflake sticker every 6 lockers and a snowman sticker every 8 lockers. To find the lockers where both stickers are places, we must find the LCM of 6 and 8:

6 = 2*3

8 = 2*2*2

Multiplying the common factors the maximum number of times it appears:

LCM = 2*2*2*3 = 24

Thus, every 24 lockers there are two stickers until Lin reaches the last 100th locker along the halfway.

The sequence of lockers is:

24, 48, 72, 96

7 0
3 years ago
Use binomial expansion to solve each exercise. (a) Find the coefficient of xy19 in (3x − 2y) 20.(b) Give a formula for the coeff
pishuonlain [190]

9514 1404 393

Answer:

  (a) -29,884,416

  (b) C(n,(n -k)/2) . . . where C(n,k) = n!/(k!(n-k)!) and k ∈ ℕ

Step-by-step explanation:

(a) The coefficient of the k-th term of the expansion is ...

  C(20,k)(3x)^(20-k)(-2y)^k

For k=19, this is ...

  19(3x)(-2y)^19 = -29,884,416xy^19

The coefficient of the term is -29,884,416.

__

(b) The p-th term of the expansion of (x +1/x)^n is ...

  C(n,p)(x^(n-p)(1/x)^p = C(n,p)(x^(n-2p))

For some exponent k of x, the value of p will be ...

  k = n -2p

  p = (n -k)/2

Then the coefficient of x^k will be C(n, (n-k)/2), where C(n, x) = n!/(x!(n-x)!).

You will notice that there will only be a term x^k for k having the same parity as n.

5 0
3 years ago
What is (11-8)-2x6+32x56÷72?
Phantasy [73]
15.889 or 15.8888999 because when you solve the 8 and 9 is a rbeing repeated,
7 0
3 years ago
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