The power dissipated by the LED is 20 Watts and the work done for 1 hour 15 minutes is 56.25 kJ.
<h3>What is electrical power?</h3>
Electrical power is the rate at which electrical work is done.
- Electrical power = voltage × current
The LED is 75% efficient means that 75% of power dissipated by the LED is converted to light.
Total power dissipated = 5 × 2.5 = 12.5 Watts
- Work done = power × time (in seconds)
Work done = 12.5 × (1 × 3600 + 15 × 60)
Work done = 56250 J = 56.25 kJ
Therefore, the power dissipated by the LED is 20 Watts and the work done for 1 hour 15 minutes is 56.25 kJ.
Learn more about electrical power and work done at: brainly.com/question/23901751
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C) S waves. s waves cannot travel through liquids
Mass = momentum / velocity = 4600 / 15 = ..... Kg
Given data
*The value of battery voltage is V = 10 V
*The current flows through the resistor is I = 5 A
The formula for the resistor is given by the Ohm's law as
Substitute the values in the above expression as
Answer:
The current in wire resistance 2Ω
a). 8696 A
b). fraction power 15.1% a 115kV
Explanation:
Resistance
Ω/Km*40km
R=2Ω
P=1000 MW
a).
Using law ohm
b).
%
