Answer:
The drift speed of the electrons in the wire is 2.12x10⁻⁴ m/s.
Explanation:
We can find the drift speed by using the following equation:
Where:
I: is the current = 4.50 A
n: is the number of electrons
q: is the modulus of the electron's charge = 1.6x10⁻¹⁹ C
A: is the cross-sectional area = 2.20x10⁻⁶ m²
We need to find the number of electrons:
Now, we can find the drift speed:
Therefore, the drift speed of the electrons in the wire is 2.12x10⁻⁴ m/s.
I hope it helps you!
<h2>Answer </h2>
<h3>1) iron </h3>
<h3>2) Aluminium </h3>
<h3>3) sliver </h3>
<h3>4) copper </h3>
I hope it's helpful for you ☺️
Answer:
option D
Explanation:
five
hope it helps you and Mark me down as brainlist
Answer:
66.35m/s
Explanation:
Para resolver el ejercicio es necesario la aplicación de las ecuaciones de continuidad, que expresan que
From our given data we can lower than:
So using the continuity equation we have
Therefore the velocity at the exit end is 66.35m/s
Answer:
30 hours
15 hours.
Explanation:
Let the Kelly used sprinkler for t hours and Gracia used the sprinkler for the rest ie (45 - t) hours .
Water output by Kelly = (35 x t) L
Water output by Gracia = 20 ( 45 - t ) L
Total output = 35t + 20(45 - t)
So, 35 t + 20 (45 - t ) = 1350
35 t + 900 - 20 t = 1350
15 t = 450
t = 30 hours
So Kelly used sprinkler for 30 hours and Gracia used it for 45 - 30 = 15 hours.
