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MA_775_DIABLO [31]
3 years ago
7

1.What is laser? 2.List the uses of laser in everyday life

Physics
1 answer:
oee [108]3 years ago
8 0

Laser means Light Amplication by Stimulated Emission of Radiation.

Uses of laser

DNA sequencing instrument

Cutting and welding materials

Semiconducting chip manufacturing

Military devices

IF YOU LIKE MY ANSWER MARK AS BRAINLIEST

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Explain the different methods that can be used to model the motion of an object.
Simora [160]

Answer:

You can describe the motion of an object by its position, speed, direction, and acceleration. An object is moving if its position relative to a fixed point is changing. idk if this helps.

Explanation:  

5 0
3 years ago
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What is a real life example of something impermeable? (please help now!!) (due tomorrow!!)
Nutka1998 [239]
Impermeable is a substance that is water proofed e.g glass, aluminium e.t.c <span />
6 0
4 years ago
An object at 20∘c absorbs 25.0 j of heat. what is the change in entropy δs of the object?
anastassius [24]
From the definition of entropy, the entropy change of an object is
\delta S =  \frac{Q}{T}
where
Q is the heat absorbed
T is the absolute temperature

in our problem, we have Q=25.0 J, while the absolute temperature is (converting in Kelvin)
T=20 ^{\circ}C + 273 = 293 K

and so the entropy change is
\delta S=  \frac{25.0 J}{293 K}=0.085 JK^{-1}
5 0
4 years ago
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A turtle accelerates from a stop at 3m/s/s to the South for 8s. What is the turtle’s final velocity? Show your work and include
andrey2020 [161]

He's accelerating at 3 m/s² .  That means his speed is increasing by 3 m/s every second.At the end of 8 seconds, his speed is (8 x 3 m/s)  =  24 m/s .He's been moving south for the whole 8 seconds.So at the end of that time, his velocity is                          24 m/s south .

5 0
3 years ago
La resistencia de un termómetro de platino es de 6Ω a30°C. Hallar su valor correspondiente a 100°C,sabiendo que el coeficiente d
Sonja [21]

Respuesta:

7,6 Ω

Explicación:

Paso 1: Información dada

  • Resistencia a 30 °C (R₀): 6 Ω
  • Coeficiente de temperatura (α): 0,00392 °C⁻¹

Paso 2: Hallar la resistencia (R) a 100 °C

Podemos ver la relación entre la resistencia de un material y la temperatura usando la siguiente ecuación.

R = R₀ (1  + α × ΔT)

R = 6 Ω (1  + 0,00392 °C⁻¹ × (100 °C - 30 °C)) = 7,6 Ω

6 0
3 years ago
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