We can't look at Figure 4. We don't know where a and b are. We can't see the blue shaded area. We don't know what our method above was. We can't see the green skinny rectangle.
Answer: - 452.088joule
Explanation:
Given the following :
Mass of water = 12g
Change in temperature(Dt) = (11 - 20)°C = - 9°C
Specific heats capacity of water(c) = 4.186j/g°C
Q = mcDt
Where Q = quantity of heat
Q = 12g × 4.186j/g°C × - 9°C
Q = - 452.088joule
Answer:
(a) 49.0 mm
Explanation:
#First we need to calculate the height of the mercury arm:
Reduced pressure is 715.7torr, Initial Pressure is 797.3torr, Required pressure is:
The difference in the two arms will give the pressure difference between the gas placed in the flask attached to an open-end mercury manometer.

Hence the height of the mercury in the arm is 49.00mm
Answer:
Therefore,
The speed of the wave on the longer wire is 95 m/s.
Explanation:
Given:
For Short wire, speed is

Let length of Short and Longer wire be
such that

To Find:
Speed on the longer wire
Solution:
The speed of a pulse or wave on a string under tension can be found with the equation,

Where,
= Tension on the wire
L = Length of Sting
m = mass of String
So here we have,
= same

Therefore,
......equation ( 1 )
And
.......equation ( 2 )
Dividing equation 1 by equation 2 and on Solving we get

Therefore,

Therefore,
The speed of the wave on the longer wire is 95 m/s.