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MA_775_DIABLO [31]
3 years ago
7

1.What is laser? 2.List the uses of laser in everyday life

Physics
1 answer:
oee [108]3 years ago
8 0

Laser means Light Amplication by Stimulated Emission of Radiation.

Uses of laser

DNA sequencing instrument

Cutting and welding materials

Semiconducting chip manufacturing

Military devices

IF YOU LIKE MY ANSWER MARK AS BRAINLIEST

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If a planet's orbital speed is 20 km/s when it's at its average distance from the sun which is most likely orbital speed when it
Alona [7]

Answer:25km/s

Explanation:

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Now, look at a general function f(x), as shown in (Figure 4) .
Nataliya [291]
We can't look at Figure 4. We don't know where a and b are. We can't see the blue shaded area. We don't know what our method above was. We can't see the green skinny rectangle.
7 0
3 years ago
How much energy (in Joules) is released when 12.0 g of water cools from 20.0 °C to 11.0 °C? This is a grade 10 question from the
KATRIN_1 [288]

Answer: - 452.088joule

Explanation:

Given the following :

Mass of water = 12g

Change in temperature(Dt) = (11 - 20)°C = - 9°C

Specific heats capacity of water(c) = 4.186j/g°C

Q = mcDt

Where Q = quantity of heat

Q = 12g × 4.186j/g°C × - 9°C

Q = - 452.088joule

7 0
3 years ago
If the gas inside the flask in the above exercise is cooled so that its pressure is reduced to a value of 715.7 torr, what will
evablogger [386]

Answer:

(a) 49.0 mm

Explanation:

#First we need to calculate the height of the mercury arm:

Reduced pressure is 715.7torr, Initial Pressure is 797.3torr, Required pressure is:

P_g_a_s=P_a_t_m+P_h\\  

The difference in the two arms will give the pressure difference between the gas placed in the flask attached to an open-end mercury manometer.

P_g_a_s=P_a_t_m+P_h\\797.3=P_a_t_m+(136.4mm-103.8mm)\\P_a_t_m=764.7mm\\\\h_t_o_t_a_l=136.4mm+103.8mm=240.2mm\\\\P_g_a_s=P_a_t_m+\bigtriangleup h\\\bigtriangleup h=P_g_a_s-P_a_t_m\\\\\bigtriangleup h=715.7mm-764.7mm\\=-49mm

Hence the height of the mercury in the arm is 49.00mm

4 0
3 years ago
A wire is stretched between two posts. Another wire is stretched between two posts that are four times as far apart. The tension
Elena-2011 [213]

Answer:

Therefore,

The speed of the wave on the longer wire is 95 m/s.

Explanation:

Given:

For Short wire, speed is

v_{s}=190\ m/s

Let length of Short  and Longer wire be L_{s}\ and\ L_{l} such that

L_{l}=4\times L_{s}

To Find:

v_{l}=?  Speed on the longer wire

Solution:

The speed of a pulse or wave on a string under tension can be found with the equation,

v=\sqrt{\dfrac{F_{T}\times L}{m}

Where,

F_{T} = Tension on the wire

L = Length of Sting

m = mass of String

So here we have,

F_{T} = same

L_{l}=4\times L_{s}

Therefore,

v_{s}=\sqrt{\dfrac{F_{T}\times L_{s}}{m} ......equation ( 1 )

And

v_{l}=\sqrt{\dfrac{F_{T}\times L_{l}}{m}  .......equation ( 2 )

Dividing equation 1 by equation 2 and on Solving we get

\dfrac{v_{s}}{v_{l}}=\sqrt{\dfrac{L_{s}}{L_{l}}}

Therefore,

v_{l}=v_{s}\sqrt{\dfrac{4\times L_{s}}{L_{s}}}=190\times 2=380\ m/s

Therefore,

The speed of the wave on the longer wire is 95 m/s.

8 0
3 years ago
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