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4 years ago

Do takis burn the inside of your stomach

Physics

1 answer:

vagabundo [1.1K]4 years ago

8 0

No they are spicy but do no burn your stomach.but to much of anything is bad for you

You might be interested in

What is the escape velocity on the Venus ? Venus' mass 4.90*10^ 24 kg and radius is 6.86 * 10 ^ 6 * m

gtnhenbr [62]

The escape velocity on Venus is 9761 m/s

Explanation:

The escape velocity from a planet is the speed that an object on the surface of that planet must have in order to completely escape the gravitational field of the planet.

Mathematically, it is calculated as

$v=\sqrt{\frac{2GM}{R}}$

where

G is the gravitational constant

M is the mass of the planet

R is the radius of the planet

For Venus, we have:

$M=4.90\cdot 10^{24}kg$ is the mass

$R=6.86\cdot 10^6 m$ is the radius

Substituting, we find the escape velocity on Venus:

$v=\sqrt{\frac{2(6.67\cdot 10^{-11})(4.90\cdot 10^{24})}{6.86\cdot 10^6}}=9761 m/s$

Learn more about velocity:

brainly.com/question/5248528

#LearnwithBrainly

8 0

3 years ago

Can someone show me the work of this

Alik [6]

Answer:

use symbollab it will help u

Explanation:

7 0

3 years ago

A dog sits on a flat surface. If the dog has a mass of 13 kg, what is the normal force acting on it?

maksim [4K]

Answer:

127

Explanation:

f(n)=mg

(13)*(9.81)

127.4N

7 0

3 years ago

Consider three vectors A⃗ ,B⃗ and C⃗ all lying in the xy plane. Vector A⃗ has length 6.2 and makes an angle of 131 degrees with

vagabundo [1.1K]

Answer:

A) 2.09

B) -62.09°

Explanation:

If D = A+B+C then C = D - A - B

Converting both A and B to rectangular coordinates, we get:

A = [-4.07 , 4.68] and B = [6.19 , 3.87]

Replacing these values we can get the x and y components of C:

C = [0.98 , -1.85]

Its module is:

$|C| = \sqrt{0.98^2+(-1.85)^2}=2.09$

Its angle is:

$\alpha _c = atan(-1.85/0.98) = -62.09\°$

8 0

3 years ago

Consider an insulating sphere of radius 6 cm surrounded by a conducting sphere of inner radius 18 cm and outer radius 26 cm. Fur

dimulka [17.4K]

Answer:

$-1.7908787542\times 10^{-9}\ C$

$3.4260289211\times 10^{-9}\ C$

$1.7908787542\times 10^{-9}\ C$

$1.6351501669\times 10^{-9}\ C$

Explanation:

r = Radius

k = Coulomb constant = $8.99\times 10^{9}\ Nm^2/C^2$

Electric field is given by

$E=-\dfrac{kq}{r^2}\\\Rightarrow q=-\dfrac{Er^2}{k}\\\Rightarrow q=-\dfrac{1610\times 0.1^2}{8.99\times 10^9}\\\Rightarrow q=-1.7908787542\times 10^{-9}\ C$

The charge is $-1.7908787542\times 10^{-9}\ C$

$Q+q=\dfrac{Er^2}{k}\\\Rightarrow Q=\dfrac{Er^2}{k}-q\\\Rightarrow Q=\dfrac{120\times 0.35^2}{8.99\times 10^9}-(-1.7908787542\times 10^{-9})\\\Rightarrow Q=3.4260289211\times 10^{-9}\ C$

The charge is $3.4260289211\times 10^{-9}\ C$

The charge inside will have the polarity changed

$q=+1.7908787542\times 10^{-9}\ C$

Outside the charge will be

$3.4260289211\times 10^{-9}-1.7908787542\times 10^{-9}\\ =1.6351501669\times 10^{-9}\ C$

3 0

4 years ago