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shusha [124]
3 years ago
15

Of all individual tax returns, 37 percent include errors made by the taxpayer. If IRS examiners are assigned randomly selected r

eturns in batches of 12, find the mean and standard deviation for the number of erroneous returns per batch.
Mathematics
1 answer:
Dima020 [189]3 years ago
8 0

Answer:

mean=4.44

standard deviation=1.67

Step-by-step explanation:

The mean and standard deviation for the number of erroneous returns per batch can be calculated using binomial distribution. The binomial distribution is used because

i) There are one of two possible outcomes( error or no error) that can be categorized into success and failure.

ii) The experiment is repeated fix number of times 12.

iii) The probability of success remains constant at each trial i.e. 37%

iv) The trails are independent.The mean and standard deviation of binomial distribution are np and √npq

Here, n=12, p=0.37 and q=1-0.37=0.63

mean=12*0.37=4.44

standard deviation=√12*0.37*0.63=√2.8=1.67

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Step-by-step explanation:

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the speed that a tsunami can travel is modeled by the equation mc025-1.jpg , where s is the speed in kilometers per hour and d i
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The answer is a.0.32 km.

The speed that a tsunami can travel is modeled by the equation is s = 356√d.

It is given:
s = 200 km/h
d = ?

Now, let's substitute s in the equation and find d:
s = 356√d
200 = 356√d
√d = 200 ÷ 356
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Now, let's square both sides of the equation:
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Mr. Whitman gave a test to his 32 math students. He felt the results were low, so he retested them one week later. The results o
Liono4ka [1.6K]

The number of student more passed the retake, when the students need a 65 in order to pass the test is 8.

<h3>What is box and whiskers plot?</h3>

Box plot is the way of representation of data which gives the graphical image of the data set to understand better. In this the data is represented with the help of quartile.

  • A.The difference in the median grade-

The median of first test is 60 while the second test is 80. Thus, the difference is,

d=80-60\\d=20

  • B. Compare the percent of students who got at least a 60 on the original test to those that got at least a 60 on the retake.

The student, who got at least 60 in first test, falls in the second half of the plot. Thus, the 50% of students got atleast 60% marks. In the retake test, all 100% student got at least 60 on test.

  • C. If the students need a 65 in order to pass the test, how many more passed the retake?

In the first test 1/4 are passed while in second test 3/4 students are passed and got the marks 65 or more than this, Thus the number of student pass more in this test,

n=(\dfrac{3}{4}-\dfrac{1}{2})\times 32\\n=8

Thus, the number of student more passed the retake, when the students need a 65 in order to pass the test is 8.

Learn more about the box and whiskers plot here;

brainly.com/question/9559392

#SPJ1

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2 years ago
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