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eduard
2 years ago
14

Jacob has $1,000 in a checking account and withdraws $40 each week. His account requires a minimum balance of more than $400. Wr

ite an inequality to model the number of weeks, x, that he can withdraw $40 to maintain the minimum balance requirement.
Mathematics
1 answer:
vova2212 [387]2 years ago
6 0

Answer:

1000-40x>400

Step-by-step explanation:

Let's call B the balance of Jacob's checking account. Each week he withdraws $40 from his actual balance of $1000, so if x is the number of weeks, the account's balance is

B=1000-40x

The balance must be more than $400, which means

1000-40x>400

That is the inequality to model the situation. If we wanted to know the limit for x, we can solve the inequality. Operating:

1000-400>40x

600>40X

x

Or x<15

Which means Jacob can withdraw $40 14 times at most to maintain the minimum balance requirement

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2 years ago
The product of two consecutive odd integers is 782. What are the integers?
Alex Ar [27]

Call the smaller of the two odds = n

Call the next number in the sequence = n + 2

n*(n +2) = 782           Remove the brackets.

n^2 + 2n = 782          Subract 782 from both sides.

n^2 + 2n - 782 = 0    We are going to have to factor this.

Discussion

This problem can't be done the way it is written. The product of an odd integer with another odd integer is and odd integer. There are no exceptions to this. So you need to give a number that has two factors very near it's square root for this question to work.

For example, you could use 783, (which factors) instead of 782 .

Solve

n^2 + 2n - 783 = 0

(n + 29)(x - 27) = 0

<u>Solution One</u>

n - 27 = 0

n = 27

The two odd consecutive integers are 27 and 29.

<u>Solution Two</u>

n + 29 = 0

n = - 29

The two solution integers are -29 and - 27 Notice that - 29 is smaller than - 27.

7 0
3 years ago
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