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Anarel [89]
3 years ago
8

Sorry about the background noise

Mathematics
1 answer:
cricket20 [7]3 years ago
4 0

Answer:

yeah how could background music be math ?? Cam is right ..

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How do you find the value of c that satisfy the equation:
victus00 [196]

Answer:

The value of c = -0.5∈ (-1,0)

Step-by-step explanation:

<u>Step(i)</u>:-

Given function f(x) = 4x² +4x -3 on the interval [-1 ,0]

<u> Mean Value theorem</u>

Let 'f' be continuous on [a ,b] and differentiable on (a ,b). The there exists a Point 'c' in (a ,b) such that

f^{l} (c)  = \frac{f(b) -f(a)}{b-a}

<u>Step(ii):</u>-

Given  f(x) = 4x² +4x -3 …(i)

Differentiating equation (i) with respective to 'x'

          f¹(x) = 4(2x) +4(1) = 8x+4

<u>Step(iii)</u>:-

By using mean value theorem

f^{l} (c)  = \frac{f(0) -f(-1)}{0-(-1)}

8c+4 = \frac{-3-(4(-1)^2+4(-1)-3)}{0-(-1)}

8c+4 = -3-(-3)

8c+4 = 0

8c = -4

c = \frac{-4}{8} = \frac{-1}{2} = -0.5

c ∈ (-1,0)

<u>Conclusion</u>:-

The value of c = -0.5∈ (-1,0)

         

<u></u>

8 0
3 years ago
Simplify this (2x)^{3}
Margaret [11]

Answer:

8x^3

Step-by-step explanation:

(2x)3

=(2x)3

=2x*2x*2x

=8x^3

7 0
2 years ago
He takes a random sample of 49 recent charterholders and computes a mean salary of $172,000 with a standard deviation of $35,000
uysha [10]

Answer:

the 90% of confidence intervals for the average salary of a CFA charter holder

 (1,63,775 , 1,80,000)

Step-by-step explanation:

<u>Explanation</u>:-

random sample of n = 49 recent charter holders

mean of sample (x⁻) =  $172,000

standard deviation of sample( S) = $35,000

Level of significance α= 1.645

<u> 90% confidence interval</u>

(x^{-} - Z_{\alpha } \frac{s}{\sqrt{n} } , x^{-} + Z_{\alpha } \frac{s}{\sqrt{n} })

(172000 - 1.645 \frac{35000}{\sqrt{49} } , 172000 +1.645 \frac{35000}{\sqrt{49} })

on calculation , we get

(1,63,775 , 1,80,000)

The mean value lies between the 90% of confidence intervals

(1,63,775 , 1,80,000)

4 0
3 years ago
Find the sum of the counting numbers from 1 to 25 inclusive. In other words, if S = 1 + 2 + 3 + ... + 24 + 25, find the value of
Anastaziya [24]

Answer:

325

Step-by-step explanation:

You must have heard about Arithmetic Progressions (AP)

Arithmetic progressions are a series of numbers such that every successive number is the sum of a constant number and the previous number.

Our very own counting numbers form AP

For example :-

2 = 1 + <u>1</u>

3 = 2 + <u>1</u>

4 = 3 + <u>1</u>

The number in bold (1) is that constant number which is added to a number to form its successive number.

To find the sum of series forming AP, we use the formula :-

sum =  \frac{n}{2} \{ a  + a  _{n}  \}

here,

  • n is the number of terms
  • a is the first number of the series
  • an is the last number of the series

So we'll use all this information to find the sum of continuous numbers from 1 to 25 where 1 is the first term(a) and 25 is the last(an).

and n is 25

S  =   \frac{25}{2}\{ 1  +25\}

=  \frac{25 \times 26}{2}

= 25  \times 13

= 325

So, the value of S comes out to be 325.

8 0
3 years ago
Read 2 more answers
Solve for n: n + (-20) = 22<br> A. 2<br> B. -42<br> C. 44<br> D. None of the above
kifflom [539]
D 44-20=22 so yea i need 20 characters so i’m still typing
8 0
3 years ago
Read 2 more answers
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