Answer:
Horizontal Asymptote: x = 0
Vertical Asymptote: x = 5
Step-by-step explanation:
The function is given as 
<em>Horizontal asymptotes are found by equating numerator to 0 and solving for x</em>
<em>Vertical asymptotes are found by equating denominator to 0 and solving for x</em>
<em />
<u>Horizontal Asymptote:</u>
x = 0
<u>Vertical Asymptote:</u>
x - 5 = 0
x = 5
This gives you three simultaneous equations:
6 = a + c
7 = 4a + c
1 = c
<u>c = 1
</u><u /><u />
If c =1,
6 = a + 1
<u>a = 5
</u><u /><u />
This doesn't work in the second equation, so the quadratic that goes through these points is not in the form y = ax^2 + bx + c
Was there supposed to be a b in the equation?
Answer:
22
Step-by-step explanation:
5*5=25
25-3=22
X=-8/z-2y...
z=2y-8/x...
y=xz/2+4
Answer:
k(x) = |x - 4| - 2
Step-by-step explanation:
So we know that k(x) is shifted 4 untis to the right and 2 units down. In an absolute value function, the value you move to the left will be positive and the value you move to the right will be negative. Since we are moving to the right, our value will be negative.
When you shift the function up or down, you will either subtract or add that value out side the absolute value. Since we are shifting down 2 units, that means we will be subtracting by 2.
Best of Luck!
