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meriva
2 years ago
14

[3]{x+1} =2x+2" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Lina20 [59]2 years ago
4 0
The answer is down below

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A communications channel transmits the digits 0 and 1. However, due to static, the digit transmitted is incorrectly received wit
m_a_m_a [10]

Answer:

The probability that the message will be wrong when decoded is 0.05792

Step-by-step explanation:

Consider the provided information.

To reduce the chance or error, we transmit 00000 instead of 0 and 11111 instead of 1.

We have 5 bits, message will be corrupt if at least 3 bits are incorrect for the same block.

The digit transmitted is incorrectly received with probability p = 0.2

The probability of receiving a digit correctly is q = 1 - 0.2 = 0.8

We want the probability that the message will be wrong when decoded.

This can be written as:

P(X\geq3) =P(X=3)+P(X=4)+P(X=5)\\P(X\geq3) =\frac{5!}{3!2!}(0.2)^3(0.8)^{2}+\frac{5!}{4!1!}(0.2)^4(0.8)^{1}+\frac{5!}{5!}(0.2)^5(0.8)^0\\P(X\geq3) =0.05792

Hence, the probability that the message will be wrong when decoded is 0.05792

4 0
3 years ago
What goes on top? For the 16 and 17 ?
san4es73 [151]
The answer to the question that needs to go on the top is 33
4 0
3 years ago
Read 2 more answers
The net of the figure shown is made of which set of
vodka [1.7K]

Answer:

Step-by-step explanation:

The sides of the base are each 5 inches. We see 4 right angles so that we are dealing with a square.

The triangles look to be isosceles. In any event there are 4 of them. So the answer is the 3rd one down.

7 0
3 years ago
Read 2 more answers
Please help!! Will put most brainliest!! Picture inserted
Llana [10]
Perpendicular to the base.
Hope this helps!!!
8 0
3 years ago
Situation D: Suppose that, in a one-minute period during an electrical storm, the number of lightning strikes on a radar antenna
Crank

Answer:

21.77% probability that the antenna will be struck exactly once during this time period.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

In this question:

\mu = 2.40

Find the probability that the antenna will be struck exactly once during this time period.

This is P(X = 1).

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 1) = \frac{e^{-2.40}*2.40^{1}}{(1)!} = 0.2177

21.77% probability that the antenna will be struck exactly once during this time period.

3 0
3 years ago
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