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2 years ago

Ahem HELP ME PLEASE! WILL GIVE BRAINLIEST

Mathematics

2 answers:

crimeas [40]2 years ago

8 0

I’m pretty sure that the answer is the last option

meriva2 years ago

5 0

Answer: The answer is B

Step-by-step explanation: Can I get brainliest

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Find the equivalent expression 9 ( 2a + 1

aivan3 [116]

Answer:

Equivalent expression of $9(2a+1)$ is, $18a+9$

Step-by-step explanation:

The distributive property says that:

$a \cdot (b+c) = a\cdot b + a\cdot c$

Given the expression: $9(2a+1)$

Apply the distributive property:

$9 \cdot (2a) +9 \cdot 1$

Simplify:

$18a+9$

Therefore, the equivalent expression of $9(2a+1)$ is, $18a+9$

8 0

3 years ago

Read 2 more answers

Find the inverse of the given matrix, if it exists.Aequals=left bracket Start 3 By 3 Matrix 1st Row 1st Column 1 2nd Column 0 3

BabaBlast [244]

Answer:

$A^{-1}=\left[ \begin{array}{ccc} \frac{1}{9} & \frac{4}{27} & - \frac{2}{27} \\\\ \frac{8}{9} & \frac{5}{27} & \frac{11}{27} \\\\ - \frac{4}{9} & \frac{2}{27} & - \frac{1}{27} \end{array} \right]$

Step-by-step explanation:

We want to find the inverse of $A=\left[ \begin{array}{ccc} 1 & 0 & -2 \\\\ 4 & 1 & 3 \\\\ -4 & 2 & 3 \end{array} \right]$

To find the inverse matrix, augment it with the identity matrix and perform row operations trying to make the identity matrix to the left. Then to the right will be inverse matrix.

So, augment the matrix with identity matrix:

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 4&1&3&0&1&0 \\\\ -4&2&3&0&0&1\end{array}\right]$

Subtract row 1 multiplied by 4 from row 2

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ -4&2&3&0&0&1\end{array}\right]$

Add row 1 multiplied by 4 to row 3

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&2&-5&4&0&1\end{array}\right]$

Subtract row 2 multiplied by 2 from row 3

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&0&-27&12&-2&1\end{array}\right]$

Divide row 3 by −27

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]$

Add row 3 multiplied by 2 to row 1

$\left[ \begin{array}{ccc|ccc}1&0&0&\frac{1}{9}&\frac{4}{27}&- \frac{2}{27} \\\\ 0&1&11&-4&1&0 \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]$

Subtract row 3 multiplied by 11 from row 2

$\left[ \begin{array}{ccc|ccc}1&0&0&\frac{1}{9}&\frac{4}{27}&- \frac{2}{27} \\\\ 0&1&0&\frac{8}{9}&\frac{5}{27}&\frac{11}{27} \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]$

As can be seen, we have obtained the identity matrix to the left. So, we are done.

6 0

3 years ago

What is the standard form when your ordered pairs are (4,5) and your slope is 5/4?

koban [17]

The slope (m) and the ordered pairs are given.
In order to arrive at the standard form : AX + BY = C, we need to form the slope-intercept form first : y = mx + b

Substitute the values in order to get the intercept (b)
y = mx + b
5 = 5/4 * 4 + b
5 = 5 + b
b = 0

So given the m = 5/4, b = 0
y = mx + b
y = 5/4x+ 0

Converting it to Standard Form
y = 5/4x + 0
5/4x - y = 0 (multiply both sides by 4)
5x - 4y = 0

So the Standard form is 5x - 4y = 0

3 0

3 years ago

I NEED HELP PLEASE. THANK YOU

vova2212 [387]

Answer:

Given

Distributive property

Subtraction property of equality

Simplify

Subtraction property of equality

Simplify

Division property of equality

Simplify

Step-by-step explanation:

If you want an explanation I would be happy to provide you with one, but I do not want to have to explain the entire thing right here because it would be really long.

7 0

3 years ago

Please help im beggih

Lana71 [14]

Number 17 is A and18 is F

7 0

3 years ago

*Ahem* HELP ME PLEASE! WILL GIVE BRAINLIEST

Ahem HELP ME PLEASE! WILL GIVE BRAINLIEST