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JulsSmile [24]
3 years ago
7

An electric field from a charge has a magnitude of 1.5 × 104 N/C at a certain location that points inward. If another charge wit

h a magnitude of +3.0 × 10−6 C is brought near it, what is the strength of the electrostatic force that acts on this charge and how do the two charges behave?
Physics
2 answers:
zysi [14]3 years ago
6 0

Answer:

-0.045 N, they will attract each other

Explanation:

The strength of the electrostatic force exerted on a charge is given by

F=qE

where

q is the magnitude of the charge

E is the electric field magnitude

In this problem,

q=3.0\cdot 10^{-6}C

E=-1.5\cdot 10^4 N/C (negative because inward)

So the strength of the electrostatic force is

F=(-3.0\cdot 10^{-6}C)(1.5\cdot 10^4 N/C)=-0.045 N

Moreover, the charge will be attracted towards the source of the electric field. In fact, the text says that the electric field points inward: this means that the source charge is negative, so the other charge (which is positive) is attracted towards it.

FrozenT [24]3 years ago
5 0

Answer:

The correct answer is actually -0.045; attract each other

Explanation:

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A woman with a mass of 52.0 kg is standing on the rim of a large disk that is rotating at an angular velocity of 0.470 rev/s abo
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Explanation:

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The moment of inertia of woman which is standing at the rim of a large disk is :

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I={52\times 3.9^2}

I₁ = 790.92 kg-m²

The moment of inertia of of the disk about an axis through its center is given by :

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I₂ =897.39 kg-m²

Total moment of inertia of the system is given by :

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I=790.92+897.39

I = 1688.31 kg-m²

The angular momentum of the system is :

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3 years ago
I don’t understand I need help asap
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3 years ago
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