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JulsSmile [24]
4 years ago
7

An electric field from a charge has a magnitude of 1.5 × 104 N/C at a certain location that points inward. If another charge wit

h a magnitude of +3.0 × 10−6 C is brought near it, what is the strength of the electrostatic force that acts on this charge and how do the two charges behave?
Physics
2 answers:
zysi [14]4 years ago
6 0

Answer:

-0.045 N, they will attract each other

Explanation:

The strength of the electrostatic force exerted on a charge is given by

F=qE

where

q is the magnitude of the charge

E is the electric field magnitude

In this problem,

q=3.0\cdot 10^{-6}C

E=-1.5\cdot 10^4 N/C (negative because inward)

So the strength of the electrostatic force is

F=(-3.0\cdot 10^{-6}C)(1.5\cdot 10^4 N/C)=-0.045 N

Moreover, the charge will be attracted towards the source of the electric field. In fact, the text says that the electric field points inward: this means that the source charge is negative, so the other charge (which is positive) is attracted towards it.

FrozenT [24]4 years ago
5 0

Answer:

The correct answer is actually -0.045; attract each other

Explanation:

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As the plastic sphere is charged, therefore it experience an electric force when placed in an electric fields and also experiences gravitational force acts downward so the electric force must act upward.

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Given, q=-7.6 nC=-7.6\times10^{-9} C and  m=3.3 g= 3.3\times10^{-3} kg.

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