Answer:
the frequency of this mode of vibration is 138.87 Hz
Explanation:
Given;
length of the copper wire, L = 1 m
mass per unit length of the copper wire, μ = 0.0014 kg/m
tension on the wire, T = 27 N
number of segments, n = 2
The frequency of this mode of vibration is calculated as;
Therefore, the frequency of this mode of vibration is 138.87 Hz
Answer:
dear can you provide the circuit of the robot
Answer: He has only move 0.2 yards
Explanation: When you subtract 18.3 from 18.5 you get 0.2 and that is how much he's moved
The best and most correct answer among the choices provided by the question is decreases <span>.
</span>The potential energy of the object <span>decreases.</span>
Hope my answer would be a great help for you.
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4.096. You just have to multiply 1.6 three times. V=s^3
