Answer:
5.88×10⁸ W
Explanation:
Power = energy / time
P = mgh / t
P = (m/t) gh
P = (1.2×10⁶ kg/s) (9.8 m/s²) (50.0 m)
P = 5.88×10⁸ W
Milliliters if you're doing science.
Answer:
The workdone is
Explanation:
From the question we are told that
The potential difference is ![V = 107 mV = 107 *10^{-3} \ V](https://tex.z-dn.net/?f=V%20%20%3D%20%20107%20mV%20%3D%20%20107%20%2A10%5E%7B-3%7D%20%5C%20%20V)
Generally the charge on
is ![Q_{Na^{+}} = 1.60 *10^{-19 } \ C](https://tex.z-dn.net/?f=Q_%7BNa%5E%7B%2B%7D%7D%20%3D%201.60%20%2A10%5E%7B-19%20%7D%20%5C%20%20C)
Generally the workdone is mathematically represented as
![W = Q_{Na^{+}}V](https://tex.z-dn.net/?f=W%20%3D%20%20Q_%7BNa%5E%7B%2B%7D%7DV)
=>
=>
Answer:
The magnitude of the electric force on a protein with this charge is ![7.2\times10^{-15}\ N](https://tex.z-dn.net/?f=7.2%5Ctimes10%5E%7B-15%7D%5C%20N)
Explanation:
Given that,
Electric field = 1500 N/C
Charge = 30 e
We need to calculate the magnitude of the electric force on a protein with this charge
Using formula of electrostatic force
![F=Eq](https://tex.z-dn.net/?f=F%3DEq)
Where, F = force
E = electric field
q = charge
Put the value into the formula
![F=1500\times30\times1.6\times10^{-19}](https://tex.z-dn.net/?f=F%3D1500%5Ctimes30%5Ctimes1.6%5Ctimes10%5E%7B-19%7D)
![F=7.2\times10^{-15}\ N](https://tex.z-dn.net/?f=F%3D7.2%5Ctimes10%5E%7B-15%7D%5C%20N)
Hence, The magnitude of the electric force on a protein with this charge is ![7.2\times10^{-15}\ N](https://tex.z-dn.net/?f=7.2%5Ctimes10%5E%7B-15%7D%5C%20N)