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Leviafan [203]
3 years ago
5

Can anybody answer this its a science question NO LINKS !!!!

Physics
1 answer:
Zigmanuir [339]3 years ago
8 0

Answer:

1) Potential energy (gravitation)

2)Potential energy

3)Kinetic energy

4) Kinetic energy

5)Potential energy

6)Kinectic energy

7)Potential energy (elastic)

Hope it helps

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Cathy, a 460-N actress playing Peter Pan, is hoisted above the stage in order to "fly" by a stagehand pulling with a force of 60
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Explanation:

Given

Weight of Cathy W_1=460\ N

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M.A.=\frac{Load}{Pulling\ effort}

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The speed of light ________ when light goes through glass.
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WHILE it's in the glass, the speed of light doesn't change.
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11. You sit at the outer rim of a Ferris wheel that rotates 2 revolutions per minute (RPM). What would your rotational speed be
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2. Which of the following is an example of acceleration.
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A 60 cm diameter wheel accelerates from rest at a rate of 7 rad/s2. After the wheel has undergone 14 rotations, what is the radi
Mamont248 [21]

Answer:

a=368.97\ m/s^2

Explanation:

Given that,

Initial angular velocity, \omega=0

Acceleration of the wheel, \alpha =7\ rad/s^2

Rotation, \theta=14\ rotation=14\times 2\pi =87.96\ rad

Let t is the time. Using second equation of kinematics can be calculated using time.

\theta=\omega_it+\dfrac{1}{2}\alpha t^2\\\\t=\sqrt{\dfrac{2\theta}{\alpha }} \\\\t=\sqrt{\dfrac{2\times 87.96}{7}} \\\\t=5.01\ s

Let \omega_f is the final angular velocity and a is the radial component of acceleration.

\omega_f=\omega_i+\alpha t\\\\\omega_f=0+7\times 5.01\\\\\omega_f=35.07\ rad/s

Radial component of acceleration,

a=\omega_f^2r\\\\a=(35.07)^2\times 0.3\\\\a=368.97\ m/s^2

So, the required acceleration on the edge of the wheel is 368.97\ m/s^2.

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