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Mandarinka [93]
3 years ago
10

What is the difference between storm spotter and storm chaser?

Physics
1 answer:
sveta [45]3 years ago
8 0

Answer:

this is just a guess

Explanation:

a storm spotter only spots the storm and a storm chaser looks for the storm????

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What process produces radiant energy in stars?
noname [10]
"Nuclear Fusion" <span>produces radiant energy in stars

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7 0
3 years ago
You grab a car door handle in the summer (energy transfer to heat up the handle ____) and it burns you through energy transfer.
Cerrena [4.2K]

Answer: conduction

Explanation:

Because you are physically touching the handle

6 0
3 years ago
A 62.0-kg skier is moving at 6.30 m/s on a frictionless, horizontal, snow-covered plateau when she encounters a rough patch 4.90
Klio2033 [76]
Here are the missing questions:
(a) How fast is the skier moving when she gets to the bottom of the hill?
(b) How much internal energy was generated in crossing the rough patch?
Part A
The initial kinetic energy of the skier is:
E_{k0}=m\frac{v_0^2}{2}
Part of this energy is then used to do work against the force of friction. Force of friction on the horizontal surface can be calculated using following formula:
F_f=mg\mu
The work is simply the force times the length:
W_f=F_f\cdot L=mg\mu L
So when the skier passes over the rough patch its energy is:
E=E_{k0}-W_f
When the skier is going down the skill gravitational potential energy is transformed into the kinetic energy:
E_p=E_{k1}\\ mgh=E_{k1}
So the final energy of the skier is:
E_f=E_{k0}-W_f+E_{k1}\\ E_f=m\frac{v_0^2}{2}-mg\mu L+mgh=1856.86$J
This energy is the kinetic energy of the skier:
E_f=m\frac{v_f^2}{2}\\ v_f=\sqrt{\frac{2E_f}{m}}=7.74\frac{m}{s}
Part B
We know that skier lost some of its kinetic energy when crossing over the rough patch. This energy is equal to the work done by the skier against the force of friction.
E_{int}=W_f\\&#10;E_{int}=mg\mu L=894.1$J

4 0
4 years ago
A 1500kg car double its speed from 50km/h to 100km/h. By how many times does the kinetic energy from the car's forward motion in
Rashid [163]

Answer:

Explanation:

Inital KE = (1/2) m v^2 = (1/2) * 1500 * 50^2 = 1,875,000 J  

Final KE = (1/2) * 1500 * 100^2 = 7,500,000 J  

But  ,

4 * 1875000 = 7500000

so the KE has increased by 4 times.

8 0
3 years ago
Read 2 more answers
An electron is in a vacuum near Earth's surface and located at y = 0 m on a vertical y axis. At what value of y should a group o
Bingel [31]

Answer:

the bunch of 23 electrons must be placed on y axis at coordinate y = - 24.35 m.

Explanation:

As we know that the gravitational force on electron at y = 0 is counter-balanced by the weight of the electron

So we have

\frac{kq_1q_2}{r^2} = mg

here we have

q_1 = e

q_2 = 23 e

m = 9.11 \times 10^{-31} kg

also we know that

e = 1.6 \times 10^{-19} C

so we will have

\frac{(9\times 10^9)(1.6 \times 10^{-19})(23\times 1.6 \times 10^{-19})}{r^2} = (9.11 \times 10^{-31})(9.81)

\frac{5.3 \times 10^{-27}}{r^2} = 8.94 \times 10^{-30}

r = 24.35 m

so the bunch of 23 electrons must be placed on y axis at coordinate y = - 24.35 m.

7 0
3 years ago
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