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3 years ago

What is the difference between storm spotter and storm chaser?

Physics

1 answer:

sveta [45]3 years ago

8 0

Answer:

this is just a guess

Explanation:

a storm spotter only spots the storm and a storm chaser looks for the storm????

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If a runner has a speed of 8.66m/s and runs for 46.2s what distance is covered? tv = d

kati45 [8]

Answer:

$\text{Using the formula: }v=\frac{d}{t}\\\therefore vt=d\\\text{Plug and chug:}46.2(8.66)=400.092\text{ metres}$

6 0

3 years ago

You are standing on the ground. Describe two ways that you could increase the pressure between your feet and the ground.

ch4aika [34]

Answer:

1:by standing with one feet

2:by standing with your toes

Explanation:

1: by standing with one feet

2:by standing with ur toes

Pressure is inversely proportional to area, the little the area, the more the pressure.the bigger the area,the lesser the pressure

3 0

4 years ago

When a small object is launched from the surface of a fictitious planet with a speed of 52.9 m/s, its final speed when it is ver

NISA [10]

Answer:

The escape speed of the planet is 41.29 m/s.

Explanation:

Given that,

Speed = 52.9 m/s

Final speed = 32.3 m/s

We need to calculate the launched with excess kinetic energy

Using formula of kinetic energy

$K.E=\dfrac{1}{2}mv^2$

$K.E=\dfrac{1}{2}\times m\times(32.3)^2$

We need to calculate the escape speed of the planet

Using formula of kinetic energy

$\text{escape kinetic energy}=\text{launch kinetic energy}-\text{excess kinetic energy}$

$\dfrac{1}{2}mv^2=\dfrac{1}{2}mv^2-\dfrac{1}{2}mv^2$

$\dfrac{1}{2}\times v^2=\dfrac{1}{2}\times(52.9)^2-\dfrac{1}{2}\times(32.3)^2$

$v=\sqrt{2\times(\dfrac{1}{2}\times(52.9)^2-\dfrac{1}{2}\times(32.3)^2)}$

$v=41.29\ m/s$

Hence, The escape speed of the planet is 41.29 m/s.

4 0

3 years ago

Thiết kế mạch điện tử sử dụng chân ngõ ra (I/O) của arduino UNO để lái relay 12VDC/500mA sao cho chân Arduino xuất ra tín hiệu 5

myrzilka [38]

Answer:

Mình cũng không biết làm bạn ơi =)))

Explanation:

6 0

3 years ago

Let's begin with the angular acceleration of a compact disk (CD). To play music the CD must rotate at high speed while a laser r

aliya0001 [1]

Answer:

$\omega = 754 rad/s$

$t = 6.6 \times 10^{-4} s$

$\alpha = 188.5 rad/s^2$

Explanation:

Frequency of the disc is given by the

$f = 7200 rev/min$

here we know that

$f = \frac{7200}{60} rev/s$

$f = 120 rev/s$

now we have

$\omega = 2\pi f$

$\omega = 2\pi(120) = 754 rad/s$

Now we know that its angular speed is 754 rad/s

now to find the time to turn by 90 degree is given as

$t = \frac{\theta}{\omega}$

$t = \frac{\pi/2}{740} = 6.6 \times 10^{-4} s$

Now the angular acceleration is given as

$\alpha = \frac{\omega_f - \omega_i}{t}$

$\alpha = \frac{240\pi - 0}{4}$

$\alpha = 188.5 rad/s^2$

5 0

4 years ago