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3 years ago

Please help me with this will reward brainlest

Mathematics

2 answers:

Gnoma [55]3 years ago

6 0

The answer would be A, B and, D

11.38+4.03= 15.41

10+5.41=15.41

9.2+6.21=15.41

Liono4ka [1.6K]3 years ago

3 0

A) 11.38 + 4.03 = 15.41

B) 10 + 5.41 = 15.41

C) 12.38 + 2.93 = 15.31

D) 9.2 + 6.21 = 15.41

E) 7.54 + 6.87 = 14.41

Answer

A) 11.38 + 4.03 = 15.41

B) 10 + 5.41 = 15.41

D) 9.2 + 6.21 = 15.41

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Whoever can help me with my math i will mark brainliest

mezya [45]

Answer:

Step-by-step explanation:

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2 years ago

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Please Please Please help with this math problem

katovenus [111]

The revenue as a function of x is equal to -x²/20 + 920x.
The profit as a function of x is equal to -x²/20 + 840x - 6000.
The value of x which maximizes profit is 8,400 and the maximum profit is $3,522,000.
The price to be charged to maximize profit is $500.

<h3>How to express the revenue as a function of x?</h3>

Based on the information provided, the cost function, C(x) is given by 80x + 6000 while the demand function, P(x) is given by -1/20(x) + 920.

Mathematically, the revenue can be calculated by using the following expression:

R(x) = x × P(x)

Revenue, R(x) = x(-1/20(x) + 920)

Revenue, R(x) = x(-x/20 + 920)

Revenue, R(x) = -x²/20 + 920x.

Expressing the profit as a function of x, we have:

Profit = Revenue - Cost

P(x) = R(x) - C(x)

P(x) = -x²/20 + 920x - (80x + 6000)

P(x) = -x²/20 + 840x - 6000.

For the value of x which maximizes profit, we would differentiate the profit function with respect to x:

P(x) = -x²/20 + 840x - 6000

P'(x) = -x/10 + 840

x/10 = 840

x = 840 × 10

x = 8,400.

For the maximum profit, we have:

P(x) = -x²/20 + 840x - 6000

P(8400) = -(8400)²/20 + 840(8400) - 6000

P(8400) = -3,528,000 + 7,056,000 - 6000

P(8400) = $3,522,000.

Lastly, we would calculate the price to be charged in order to maximize profit is given by:

P(x) = -1/20(x) + 920

P(x) = -1/20(8400) + 920

P(x) = -420 + 920

P(x) = $500.

Read more on maximized profit here: brainly.com/question/13800671

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1 year ago

The length of human pregnancies from conception to birth varies according to an approximately normal distribution with a mean of

Varvara68 [4.7K]

Answer:

A) 68.33%

B) (234, 298)

Step-by-step explanation:

We have that the mean is 266 days (m) and the standard deviation is 16 days (sd), so we are asked:

A. P (250 x < 282)

P ((x1 - m) / sd < x < (x2 - m) / sd)

P ((250 - 266) / 16 < x < (282 - 266) / 16)

P (- 1 < z < 1)

P (z < 1) - P (-1 < z)

If we look in the normal distribution table we have to:

P (-1 < z) = 0.1587

P (z < 1) = 0.8413

replacing

0.8413 - 0.1587 = 0.6833

The percentage of pregnancies last between 250 and 282 days is 68.33%

B. We apply the experimental formula of 68-95-99.7

For middle 95% it is:

(m - 2 * sd, m + 2 * sd)

Thus,

m - 2 * sd <x <m + 2 * sd

we replace

266 - 2 * 16 <x <266 + 2 * 16

234 <x <298

That is, the interval would be (234, 298)

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2 years ago

Which is an x-intercept of the continuous function in

arsen [322]

It’s (-1,0), because

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2 years ago

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A salesperson earns a commission of a certain percentage on the original price of any items he helps you buy. The salesperson he

attashe74 [19]

Answer:

5.18%

Step-by-step explanation:

5.76 x 100 = 576

576 ÷ 100 = 5.184

5.184 = 5.18%

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2 years ago