7.

Mathematics

1 answer:

tekilochka [14]2 years ago

8 0

Answer:

I think around 15°c

Step-by-step explanation:

PLEASE accept me in brainly

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What is the domain for y=x^2-3

artcher [175]

The domain is hope this helped:)

3 0

2 years ago

Which math expression means "the product of 16 and 26"?<br> 16 +26<br> O 16.26<br> 15 - 26<br> 26-16

Llana [10]

Answer:

The product of 16 and 26 would be 16 * 26

Step-by-step explanation:

This is because "the product of" means multiplication so *. Making it 16 * 26.

8 0

2 years ago

You are thinking of using a t procedure to construct a 95% confidence interval for the mean of a population. You suspect the dis

bonufazy [111]

this makes no sense sos im only 8 years old.

5 0

2 years ago

To answer that question

Mars2501 [29]

First, we get ax^2+bx+c. Next, we know that the line of symmetry is -b/2a. Since we know that there is a maximum value, the parabola is facing downwards, so a is negative. For random numbers, we can say that a = -0.5 and b=-10 (b needs to be negative for -b/2a to equal -10), getting -0.5x^2-10x+c. Plugging -10 in for x (since -10 is the middle it is the max), we get -50+100=50. Since the maximum needs to be 5, not 50, we subtract 45 from the answer to get it and therefore make c = -45, getting -0.5x^2-10x-45

5 0

2 years ago

Enter the explicit rule for the sequence

Softa [21]

Let's take a look at the first few numbers in the sequence based on the given rule:

$a_{1}=6\\ a_{2}= \frac{1}{4}(6)\\ a_3= \frac{1}{4}\big( \frac{1}{4}\big)6= \big(\frac{1}{4}\big)^2(6)\\ a_{4}= \frac{1}{4} \big(\frac{1}{4}\big)^26= \big(\frac{1}{4}\big)^3(6)$

Inspecting this pattern it seems like the power $\frac{1}{4}$ is being raised to is always one less than the number of the sequence, so if we were on the nth number in the sequence, that part of the expression would be $\big(\frac{1}{4} \big)^{n-1}$ . We also know that we'll be multiplying whatever we get from that by 6, so we can write the full explicit rule for our sequence as

$a_n=6\big( \frac{1}{4} \big)^{n-1}$

Where $a_n$ is the nth number in our sequence.

8 0

3 years ago