Answer:
here you have to find the range
Explanation:
1.4431m
Answer:
Entropy is increasing. Entropy is decreasing.
Explanation:
The Entropy doesn't change.
Answer:
v = 0.667 m / s, m = 6746 kg
Explanation:
For this exercise we must use the relationship between work and kinetic energy
W = ΔK
the work is defined by
W = F. x
bold indicates vectors
W = F x cos θ
in this case the force is in the same direction of displacement
W = F x
F x = K_f - K₀
as the body starts from rest the initial kinetic energy is zero
F x = ½ m v²
Now let's use the relationship between momentum and momentum
I = Δp
I = F t
Δp = m v_f - m v₀
as part of rest v₀ = 0
F t = m v
Let's write our system of equations
F x = ½ m v²
F t = m v
we have a system of two equations with two unknowns, let's divide the two expressions
x / t = ½ v
v = 2x / t
v = 2 10/30
v = 0.667 m / s
we look for the mass
F t = m v
m = F t / v
m = 150 30 / 0.667
m = 6746 kg
Answer:
c. 20 amps.
just divide the watts by the volts
Answer with Explanation:
From work energy theorem we have
Now since it is given that the work done on the object by the force is positive hence we conclude that the term on the right hand of the above relation is positive hence
Part a)
Hence we conclude that the mechanical energy of the particle will increase.
Part b) Since the mechanical energy of the particle is the sum of it's kinetic and potential energies, we can write
Now since the sum of the 2 energies ( Kinetic and potential ) is positive we cannot be conclusive of the individual values since 2 cases may arise:
1) Kinetic energy increases while as potential energy decreases.
2) Potential energy increases while as kinetic energy decreases.
Hence these two cases are possible and we cannot find using only the given information which case will hold
Hence no conclusion can be formed regarding the individual energies.