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Law Incorporation [45]
3 years ago
15

You have now seen examples during lecture on how to calculate the electric field for a line of charge and a ring of charge - bot

h uniformly distributed. This activity will ask you to solve for the electric field, on-axis, of a uniformly-charged disk sitting in the yz plane. Below is a picture of the situation of interest. Note: Treat it as a totally flat disk and ignore its thickness in the x direction. Also, let x be the distance between the center of the disc and point P.
Physics
1 answer:
Shtirlitz [24]3 years ago
3 0

Answer:

1/4πε₀[Hx/ (√x² + b²)^3/2]i.

Explanation:

So, without mincing words let's dive straight into the solution to the question above. There is need to determine the electric field on-axis of a uniformly-charged disk sitting.

The electric field in the x-component, dεₓ = 1/4πε₀[H/ x² + b²] cos .

Thus, the total electric field in the x-component, εₓ = 1/4πε₀ [ xdH/ (x^2 + b^2)^3/2.

Therefore, the electric field = 1/4πε₀ [ xdH/ (x^2 + b^2)^3/2i.

Where x=0

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A boy whirls a stone in a horizontal circle of radius 1.1 m and at height 2.1 m above ground level. The string breaks, and the s
DedPeter [7]

Answer:

212.8 m/s^{2}

Explanation:

Time taken by stone to cover horizontal distance

t=\sqrt{\frac {2h}{g}} where t is time, h is height of whirling the stone in horizontal circle, g is gravitational constant, Substituting h for 2.1 m and g for 9.81

t=\sqrt{\frac {2*2.1}{9.81}}= 0.654654 seconds

t=0.65 s

Velocity, v= distance/time

v=10/0.65= 15.27525 m/s

v=15.3 m/s

a=\frac {v^{2}}{r} where r is radius of circle, substituting r with 1.1m

a=\frac {15.3^{2}}{1.1}

a=212.8 m/s^{2}

Therefore, centripetal acceleration is 212.8 m/s^{2}

8 0
3 years ago
Which of the following is an example of a chemical property? Density Solubility Flammability Magnetism
choli [55]
The answer should be flammability
8 0
3 years ago
Why do flames go upwards​
BabaBlast [244]

Answer:

Easy search it on g o o g l e

4 0
3 years ago
A plate in a parallel-plate capacitor has an area of 0.03 m2 and is 0.5 × 10–3 m from the other plate. The space between the pla
Tems11 [23]

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A. 4 × 10–9 F

4 0
3 years ago
The direction of an electric field is the direction (5 points) a negative test charge will move in the field a positive test cha
svet-max [94.6K]

Answer:

a positive test charge will move in the field

Explanation:

The direction of an electric field corresponds to the direction of motion of a positive test charge in the electric field. In fact:

- the electric field produced by a positive charge points outwards the charge --> this is because when a positive test charge is placed in this field, it will feel a repulsive force (because two positive charges repel each other), so it will move away from the positive charge that produces the field

- the electric field produced by a negative charge points towards the charge  itself--> this is because when a positive test charge is placed in this field, it will feel an attractive force (because a positive and a negative charge attract each other), so it will move toward the negative charge that produces the field.

4 0
3 years ago
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